We can also sort the ordered dictionary based upon values:

Syntax

 dict = collections.OrderedDict(sorted(d1.items(), key=lambda (k,v): v)) 
 dict = New sorted dictionary 
 d1=  Original Ordered dictionary 

Here, the lambda function changes the key to its value. As ordered, the dictionary returns the (key, value) pair. The lambda function makes key = value, thus the ordered dictionary will be sorted by its value. Let's take an example to understand the sorting of the ordered dictionary based upon values:

import collections 
print 'n Order dictionary'
d1 = collections.OrderedDict()
d1['a']= 'SAS'
d1['d']= 'PYTHON'
d1['b']= 'SAP HANNA'
d1['f']= 'R'
d1['c']= 'JULIA'

for k,v in d1.items():
   print k, ":",v
print 'n Sorted Order dictionary'
dict = collections.OrderedDict(sorted(d1.items(), key=lambda (k,v): v))

for k,v in dict.items():
      print k, ":",v

As you can clearly see from the preceding example, the lambda() function converts key to value and we can see the output as shown here: