We recall some results from the theory of power series which should already be known to the reader. Proofs and further results can be found in textbooks on Analysis, see e.g. [25, 26].
Let {an} be a sequence of complex numbers. The power series centred at zero with coefficients {an} is
i.e. the sequence of polynomials {sn(z)}n
Given a power series , the non-negative real number ρ defined by
where 1/0+ = +∞ and 1/(+∞) = 0, is called the radius of convergence of the series . In fact, one proves that the sequence {sn(z)} is absolutely convergent if |z| < ρ and it does not converge if |z| > ρ. It can be shown that ρ > 0 if and only if the sequence {|an|} is not more than exponentially increasing. In this case, the sum of the series
is defined in the disc {|z| < ρ}.
Power series can be integrated and differentiated term by term. More precisely, the following holds.
Theorem A.1 Let be the sum of a power series with radius of convergence ρ. Then the series and have the same radii of convergence ρ. If ρ > 0, then A(z) is holomorphic in B(0, ρ),
and, given any piecewise C1 curve γ : [0, 1] → B(0, ρ),
Then Corollary A.2 easily follows.
Corollary A.2 Let be the sum of a power series of radius of convergence ρ > 0. Then
Thus, if ρ > 0 the sum A(z), |z| < ρ, completely determines the sequence {an}. The function A(z) is called the generating function of the sequence {an}. In other words, {an} and contain the same ‘information’ (we are assuming that {an} grows at most exponentially or, equivalently that ρ > 0): we can say that the function A(z), |z| < ρ, is a new ‘viewpoint’ on the sequence {an}.
By Corollary A.2 if and B(z) = are the sums of two power series with positive radii of convergence, that coincide near zero, then an = bn ∀n, both series have the same radius ρ, and A(z) = B(z) for any z such that |z| < ρ.
Example A.3 (Geometric series) The geometric series is the most classical example of power series. It generates the sequence {1, 1, 1,... }
Example A.4 (Exponential) Taking advantage of Taylor expansions, one can prove that
Example A.5 (Logarithm) Replacing z with −z in the equality |z| < 1, we get
Integrating along the interval [0, x] ⊂ , we get
Definition A.6 The convolution product of two sequences a = {an} and b = {bn} is the sequence {a ∗ b}n defined for n = 0, 1, . . . by
In the first sum we sum over all couples (i, j) of non-negative integers such that i + j = n.
The first terms are
The convolution product is commutative, associative and bilinear. Moreover the following holds.
Theorem A.7 (Cauchy) Let a = {an} and b = {bn} be two sequences and let and B(z) = be the sums of the associated power series defined for |z| < ρa and |z| < ρb, respectively. Then the power series of their convolution products converges for any z such that |z| < min(ρa, ρb) and
Let V be a Banach space with norm || || and let {fn} ⊂ V. Then one may consider the series, with values in V,
Let ρ ≥ 0 be defined by
As in the case of power series with complex coefficients, the power series in (A.2) absolutely converges in V for any Thus the sum of the series is a well defined function on the disc |z| < ρ of the complex plane with values in V
As for complex valued power series, one differentiates term by term Banach valued power series: the sum F(z) is a holomorphic function on the open disc |z| < ρ and
As a special case, one considers the space MN,N () of N × N complex matrices with norm
called the maximum expansion coefficient of F. It is easy to prove that
and that MN,N () equipped with this norm is a Banach space. Given a sequence {Fn} ⊂ MN,N (), the associated power series
converges if |z| < ρ where
From the above, we have the following:
(i) ρ > 0 if and only if the sequence {||Fn||} grows at most exponentially fast.
(ii) If |z| < ρ, then the series (A.3) converges, both pointwise and absolutely, to a matrix F(z) ∈ MN,N (),
i.e. we have ∀i, j ∈ {1, . . . ,N} the complex valued limits
Let P ∈ MN,N () be a N × N square matrix with complex entries. If ||P|| |z| < 1, then Thus the series converges, both pointwisely and absolutely, to a matrix For any positive n we can write
so that
Since ||P|| |z| < 1, as n → ∞ we get
Therefore, we conclude that, if then Id − zP is invertible and
Let Q ∈ MN,N (). The radius of convergence of the power series
is +∞, so that, for any z ∈ the power series converges, both absolutely and pointwisely, to a matrix denoted by eQz,
Proposition A.8 The following hold:
(i) eQ0 = Id.
(ii) eQz and Q commute.
(iii) for any z ∈ .
(iv) eQ(z+w) = eQz eQw for any z, w ∈ .
(v) eQz is invertible and its inverse is (eQz)−1 = e−Qz.
(vi) (eQz)n = eQnz for any z ∈ and any n ∈ .
Proof. Properties (i) and (ii) are a direct consequence of the definition of eQz. Property (iii) follows differentiating term by term the series . Property (iv) is a consequence of the formula for the product of power series: in fact,
Finally, properties (v) and (vi) are particular cases of (iv).
Exercise A.9 Prove the Newton binomial theorem:
(i) directly, with an induction argument on n;
(ii) taking advantage of the Taylor expansions;
(iii) starting from the formula D((1 + z)n) = n(1 + z)n−1;
(iv) starting from the identity et(x+y) = etxety.
Exercise A.10 Prove the following equalities:
Exercise A.11 Show that
Exercise A.12 Let {an} be a complex valued sequence such that {|an|} grows at most exponentially fast. Let |z| < ρ be its generating function. Compute the generating function of the following sequences:
Solution.
We prove this equality directly. Since for any p = 1, . . ., n − 1 we have one gets
The same result can be obtained via generating functions. From the formula for the product of two power series, we get
The claim follows by the identity principle for polynomials.
Exercise A.14 For any p, q, k ≥ 0, prove Vandermonde formula
Solution. We prove the equality (A.5) by using generating functions. From the formula for the product of power series, we get
hence the claim.
Exercise A.15 Show that
Solution. Applying the Vandermonde formula (A.5), we get
Exercise A.16 Show that
Solution. Applying Vandermonde formula we get
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