Appendix A

Power series

We recall some results from the theory of power series which should already be known to the reader. Proofs and further results can be found in textbooks on Analysis, see e.g. [25, 26].

A.1   Basic properties

Let {an} be a sequence of complex numbers. The power series centred at zero with coefficients {an} is

images

i.e. the sequence of polynomials {sn(z)}n

images

Given a power series images, the non-negative real number ρ defined by

images

where 1/0+ = +∞ and 1/(+∞) = 0, is called the radius of convergence of the series images. In fact, one proves that the sequence {sn(z)} is absolutely convergent if |z| < ρ and it does not converge if |z| > ρ. It can be shown that ρ > 0 if and only if the sequence {|an|} is not more than exponentially increasing. In this case, the sum of the series

images

is defined in the disc {|z| < ρ}.

Power series can be integrated and differentiated term by term. More precisely, the following holds.

Theorem A.1 Let images be the sum of a power series with radius of convergence ρ. Then the series images and images have the same radii of convergence ρ. If ρ > 0, then A(z) is holomorphic in B(0, ρ),

images

and, given any piecewise C1 curve γ : [0, 1] → B(0, ρ),

images

Then Corollary A.2 easily follows.

Corollary A.2 Let images be the sum of a power series of radius of convergence ρ > 0. Then

images

Thus, if ρ > 0 the sum A(z), |z| < ρ, completely determines the sequence {an}. The function A(z) is called the generating function of the sequence {an}. In other words, {an} and images contain the same ‘information’ (we are assuming that {an} grows at most exponentially or, equivalently that ρ > 0): we can say that the function A(z), |z| < ρ, is a new ‘viewpoint’ on the sequence {an}.

By Corollary A.2 if images and B(z) = images are the sums of two power series with positive radii of convergence, that coincide near zero, then an = bnn, both series have the same radius ρ, and A(z) = B(z) for any z such that |z| < ρ.

Example A.3 (Geometric series) The geometric series is the most classical example of power series. It generates the sequence {1, 1, 1,... }

images

and its sum is

images

Example A.4 (Exponential) Taking advantage of Taylor expansions, one can prove that

images

Example A.5 (Logarithm) Replacing z with −z in the equality images |z| < 1, we get

images

Integrating along the interval [0, x] ⊂ images, we get

images

A.2   Product of series

Definition A.6 The convolution product of two sequences a = {an} and b = {bn} is the sequence {ab}n defined for n = 0, 1, . . . by

images

In the first sum we sum over all couples (i, j) of non-negative integers such that i + j = n.

The first terms are

images

The convolution product is commutative, associative and bilinear. Moreover the following holds.

Theorem A.7 (Cauchy) Let a = {an} and b = {bn} be two sequences and let images and B(z) = images be the sums of the associated power series defined for |z| < ρa and |z| < ρb, respectively. Then the power series of their convolution products converges for any z such that |z| < min(ρa, ρb) and

images

A.3   Banach space valued power series

Let V be a Banach space with norm || || and let {fn} ⊂ V. Then one may consider the series, with values in V,

images

Let ρ ≥ 0 be defined by

images

As in the case of power series with complex coefficients, the power series in (A.2) absolutely converges in V for any images Thus the sum of the series is a well defined function on the disc |z| < ρ of the complex plane with values in V

images

As for complex valued power series, one differentiates term by term Banach valued power series: the sum F(z) is a holomorphic function on the open disc |z| < ρ and

images

As a special case, one considers the space MN,N (images) of N × N complex matrices with norm

images

called the maximum expansion coefficient of F. It is easy to prove that

images

and that MN,N (images) equipped with this norm is a Banach space. Given a sequence {Fn} ⊂ MN,N (images), the associated power series

images

converges if |z| < ρ where

images

From the above, we have the following:

(i) ρ > 0 if and only if the sequence {||Fn||} grows at most exponentially fast.

(ii) If |z| < ρ, then the series (A.3) converges, both pointwise and absolutely, to a matrix F(z) ∈ MN,N (images),

images

i.e. we have ∀i, j ∈ {1, . . . ,N} the complex valued limits

images

A.3.1.1   Power expansion of the inverse of a matrix

Let PMN,N (images) be a N × N square matrix with complex entries. If ||P|| |z| < 1, then images Thus the series images converges, both pointwisely and absolutely, to a matrix images For any positive n we can write

images

so that

images

Since ||P|| |z| < 1, as n → ∞ we get

images

Therefore, we conclude that, if images then Id − zP is invertible and

images

A.3.1.2   Exponential of a matrix

Let QMN,N (images). The radius of convergence of the power series

images

is +∞, so that, for any zimages the power series images converges, both absolutely and pointwisely, to a matrix denoted by eQz,

images

Proposition A.8 The following hold:

(i) eQ0 = Id.

(ii) eQz and Q commute.

(iii) images for any zimages.

(iv) eQ(z+w) = eQz eQw for any z, wimages.

(v) eQz is invertible and its inverse is (eQz)−1 = eQz.

(vi) (eQz)n = eQnz for any zimages and any nimages.

Proof. Properties (i) and (ii) are a direct consequence of the definition of eQz. Property (iii) follows differentiating term by term the series images. Property (iv) is a consequence of the formula for the product of power series: in fact,

images

Finally, properties (v) and (vi) are particular cases of (iv).

A.3.2   Exercises

Exercise A.9 Prove the Newton binomial theorem:

(i) directly, with an induction argument on n;

(ii) taking advantage of the Taylor expansions;

(iii) starting from the formula D((1 + z)n) = n(1 + z)n−1;

(iv) starting from the identity et(x+y) = etxety.

Exercise A.10 Prove the following equalities:

images

Exercise A.11 Show that

images

Exercise A.12 Let {an} be a complex valued sequence such that {|an|} grows at most exponentially fast. Let images |z| < ρ be its generating function. Compute the generating function of the following sequences:

  • {αa0, αa1, αa2, αa3,...}, αimages,
  • {a0, 0, a1, 0, a2, 0,...},
  • {a0, 0, a2, 0, a4, 0,...},
  • {a1, 0, a3, 0, a5, 0,...},
  • {0, 0, 0, a0, a1, a2, a3,...},
  • {a3, a4, a5, a6,...},
  • {a0, 2a1, 3a2, 4a3, 5a4,...},
  • {a0, a1/2, a2/3, a3/4, a4/5,...},
  • {a0, a0 + a1, a1 + a2, a2 + a3,...},
  • {a0 + a1, a1 + a2, a2 + a3, a3 + a4,...},
  • {a0, a0 + a1, a0 + a1 + a2, a0 + a1 + a2 + a3,...},

Exercise A.13 Compute images

Solution.

We prove this equality directly. Since for any p = 1, . . ., n − 1 we have images one gets

images

The same result can be obtained via generating functions. From the formula for the product of two power series, we get

images

The claim follows by the identity principle for polynomials.

Exercise A.14 For any p, q, k ≥ 0, prove Vandermonde formula

images

Solution. We prove the equality (A.5) by using generating functions. From the formula for the product of power series, we get

images

hence the claim.

Exercise A.15 Show that images

Solution. Applying the Vandermonde formula (A.5), we get

images

Exercise A.16 Show that images

Solution. Applying Vandermonde formula we get

images

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