Let z = diag(z1, · · · , zr+1) be an element of the group (), which is the diagonal subgroup of GLr+1(). In the application to the Casselman-Shalika formula we will take the zi to be the Langlands parameters. (In terms of the si the zi are determined by the conditions that Π zi = 1 and zi/zi+1 = .)
Let us write the Weyl character formula in the form
where we recall that sλ(z) = sλ(z1, · · · , zr+1) is the Schur polynomial. The sum over the Weyl group on the right-hand side is the numerator in the Weyl formula and the product on the left is essentially the Weyl denominator. The Weyl vector ρ, we recall, is ρ = (r, r − 1 , · · · , 2, 1, 0).
We have seen in (4.4) and (4.2) that p-part of the Whittaker coefficient of the Eisenstein series is
The similarity of this expression to (5.1) indicates that the p-parts of Whittaker coefficients of Eisenstein series can be profitably regarded as a deformation of the numerator in the Weyl character formula.
Thus we are led to deformations of the Weyl character formula. Tokuyama [70] gave such a deformation. It is an expression of sλ(z) as a ratio of a numerator to a denominator. The denominator is a deformation of the Weyl denominator, and the numerator is a sum over Gelfand-Tsetlin patterns with top row λ + ρ. It can be rewritten as a sum over λ+ρ.
Tokuyama’s formula has a parameter t, which can be specialized in various ways. If t = 1, it is the Weyl character formula. If t = 0, it is equivalent to the combinatorial definition of the Schur polynomial as a sum over semistandard Young tableaux, that is, over λ. If t is specialized to −q−1 then the denominator in Tokuyama’s formula matches the product in (5.2). In this specialization, the numerator in Tokuyama’s formula agrees with the p-parts of the Weyl group multiple Dirichlet series in the special case n = 1.
We will state and prove Tokuyama’s formula, then translate it into the language of crystals.
If is a Gelfand-Tsetlin pattern in the notation (1.5) let s() be the number of entries aij with i > 0 such that ai−1,j−1 < aij < ai−1,j. Let l() be the number of entries aij with i > 0 such that aij = ai−1,j−1. Thus l() is the number of boxed elements in Γ(), and s() is the number of entries that are neither boxed nor circled. For 0 ≤ i ≤ r let di = di() = be the i-th row sum of .
We recall that the Schur polynomial sλ is symmetric, and if zi are the eigenvalues of g ∈ GLr+1() then sλ(z1, · · · , zr+1) = χλ(g), where χλ the character of the irreducible representation with highest weight λ. In this chapter there will be an induction on r, so we will sometimes write ρ = ρr = (r, r − 1, · · · , 0). Let GT(λ) = GTr(λ) be the set of Gelfand-Tsetlin patterns with r + 1 rows having top row λ.
THEOREM 5.1 (Tokuyama [70]) We have
For comparison with the original paper, we note that we have reversed the order of the zi, which does not affect the Schur polynomial since it is symmetric. The following proof is essentially Tokuyama’s original one.
Proof. Let Λ(r) be the ring of symmetric polynomials in z1, · · · , zr. There is a homomorphism Λ(r+1) Λ(r) in which one sets zr+1 1. The homomorphism is not injective, but its restriction to the homogeneous part of Λ of fixed degree r is injective. We note that as polynomials in the zi both sides of (5.3) are homogeneous of degree d0 = |λ| + r(r + 1). (If λ is a partition then |λ| = Σi λi. See Macdonald [64] for background on partitions and symmetric functions.) Two homogeneous polynomials of the same degree are equal if they are equal when zr+1 = 1, so it is sufficient to show that (5.3) is true when zr+1 = 1, and for this we may assume inductively that the formula is true for r − 1.
The branching rule from GLr+1() to GLr(), already mentioned in connection with (2.4), may be expressed as
See for example Bump [19], Chapter 44.
Also on setting zr+1 = 1,
becomes
where ek is the k-th elementary symmetric polynomial, that is, the sum of all squarefree monomials of degree k.
Now we recall Pieri’s formula in the form
See for example Bump [19], Chapter 42. The notation v⊥|μ| + k means that v is a partition of |μ| + k. The condition that vμ is a vertical strip means that the Young diagram of v contains the Young diagram of μ, and that the skew-diagram vμ has no two entries in the same row. Thus vμ is a vertical strip if and only if each vi = μi or μi + 1, and since v⊥|μ| + k, it follows that vi = μi + 1 exactly k times. Thus when zr+1 = 1 the right-hand side of (5.3) becomes
Now by induction
where are the row sums of ′. We substitute this and interchange the order of summation and make the summation over μ the innermost sum. The condition that vμ is a vertical strip means that μi ≤ vi ≤ μi + 1. Combining this with the fact that μ interleaves λ we have
and therefore v + ρr−1 interleaves λ + ρr. Since k = |v| − |μ|, the right-hand side of (5.3), with zr+1 specialized to 1, equals
Now we assemble λ + ρr and the Gelfand-Tsetlin pattern ′ into a big Gelfand-Tsetlin parterns . The row sums of and ′ are the same except the top row, so di = for 1 ≤ i ≤ r. We may just as well sum over , in which case ′ is the pattern obtained by discarding the top row of . We get
We evaluate the term in brackets. It is
We now show that this equals (t + 1)s()−s(′)tl()−l(′). By (5.5), if vi = λi + 1 then vi = μi + 1 and so The number of such terms is l() − l(′) and so we have a contribution of tl()−l(′). If vi = λi+1, then (5.5) implies that vi = μi and these factors equal 1. Hence they may be discarded from the product. In the remaining cases we have λi + 1 > vi > λi+1 both t and 1 can occur. The number of such terms is s() − s(′), and so we have a contribution of (t + 1)s()−s(′). Hence the term in brackets equals where ltop() is number of boxed entries in the top row of Γ() and stop() is the number of entries in the top row of Γ() that are neither boxed nor circled. Clearly l() = l(′) + ltop() and s() = s(′) + stop() so we obtain the left-hand side of (5.3), with zr+1 = 1. This completes the induction.
We will give a version of Tokuyama’s formula for crystals. We will take n = 1 in (1.15). In this case the Gauss sums may be evaluated explicitly and
g(a) = qagb, h(a) = qahb
where
gb = gb(a) = −q−1, hb = hb(a) = (q − 1)q−1
are independent of a.
LEMMA 5.2 If υ ∈ λ+ρ then
Proof. If υ is non-strict then some ai,j = ai,j+1. This means that
ai,j = ai+1,j+1 = ai,j+1
and so the entry Γi+1,j+1 is both boxed and circled in Γ(υ), which implies that . On the other hand if υ is strict then
which clearly equals and the statement is proved.
THEOREM 5.3 If λ is a dominant weight, and if z1, · · · , zr+1 are the eigenvalues of q ∈ GLr+1(), then
Proof. We will prove this in the form
This is equivalent since
By Theorem 5.1 with t = −q−1, the right-hand side of (5.6) equals
Turning to the left-hand side of (5.6), let υ ∈ λ+ρ. By (2.17) we have zwt(υ) = . Combining this with Lemma 5.2, we obtain (5.6).
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