8
Transverse Vibration of Strings

8.1 INTRODUCTION

It is well known that most important musical instruments, including the violin and the guitar, involve strings whose natural frequencies and mode shapes play a significant role in their performance. The characteristics of many engineering systems, such as guy wires, electric transmission lines, ropes and belts used in machinery, and thread manufacture, can be derived from a study of the dynamics of taut strings. The free and forced transverse vibration of strings is considered in this chapter. As will be seen in subsequent chapters, the equation governing the transverse vibration of strings will have the same form as the equations of motion of longitudinal vibration of bars and torsional vibration of shafts.

8.2 EQUATION OF MOTION

8.2.1 Equilibrium Approach

Figure 8.1 shows a tightly stretched elastic string or cable of length l subjected to a distributed transverse force images per unit length. The string is assumed to be supported at the ends on elastic springs of stiffness images and images. By assuming the transverse displacement of the string images to be small, Newton's second law of motion can be applied for the motion of an element of the string in the z direction as

Schematic diagrams depicting (a) Vibrating string; (b) differential element with of length l, transverse force f(x, t), stiffness k1 and k2.

Figure 8.1 (a) Vibrating string; (b) differential element.

If images is the tension, images is the mass per unit length, and images is the angle made by the deflected string with the x axis, Eq. (8.1) can be rewritten, for an element of length images, as

Noting that

(8.3)equation
(8.4)equation
(8.5)equation

Eq. (8.2) can be expressed as

If the string is uniform and the tension is constant, Eq. (8.6) takes the form

For free vibration, images and Eq. (8.7) reduces to

which can be rewritten as

where

(8.10)equation

Equation (8.9) is called the one‐dimensional wave equation.

8.2.2 Variational Approach

Strain Energy    There are three sources of strain energy for the taut string shown in Fig. 8.1. The first is due to the deformation of the string over images, where the tension images tries to restore the deflected string to the equilibrium position; the second is due to the deformation of the spring at images; and the third is due to the deformation of the spring at images. The length of a differential element dx in the deformed position, ds, can be expressed as

(8.11)equation

by assuming the slope of the deflected string, images, to be small. The strain energy due to the deformations of the springs at images and images is given by images and images, and the strain energy associated with the deformation of the string is given by the work done by the tensile force images while moving through the distance images:

(8.12)equation

Thus, the total strain energy, images, is given by

(8.13)equation

Kinetic Energy    The kinetic energy of the string is given by

(8.14)equation

where images is the mass of the string per unit length.

Work Done by External Forces    The work done by the nonconservative distributed load acting on the string, images, can be expressed as

(8.15)equation

Hamilton's principle gives

or

The variations of the individual terms appearing in Eq. (8.17) can be carried out as follows:

using the interchangeability of the variation and differentiation processes. Equation (8.18) can be evaluated by using integration by parts with respect to time:

Using the fact that images at images and images and assuming images to be constant, Eq. (8.19) yields

The second term of Eq. (8.16) can be written as

By using integration by parts with respect to x, Eq. (8.21) can be expressed as

The third term of Eq. (8.16) can be written as

By inserting Eqs. (8.20), (8.22), and (8.23) into Eq. (8.16) and collecting the terms, we obtain

Since the variation images over the interval images is arbitrary, Eq. (8.24) can be satisfied only when the individual terms of Eq. (8.24) are equal to zero:

Equation (8.25) denotes the equation of motion while Eqs. (8.26) and (8.27) represent the boundary conditions. Equation (8.26) can be satisfied when images or when images. Since the displacement images cannot be zero for all time at images, Eq. (8.26) can only be satisfied by setting

Similarly, Eq. (8.27) leads to the condition

Thus, the differential equation of motion of the string is given by Eq. (8.25) and the corresponding boundary conditions by Eqs. (8.28) and (8.29).

8.3 INITIAL AND BOUNDARY CONDITIONS

The equation of motion, Eq. (8.6), or its special forms Eqs. (8.7) and (8.8) or (8.9), is a partial differential equation of order 2 in x as well as t. Thus, two boundary conditions and two initial conditions are required to find the solution, images. If the string is given an initial deflection images and an initial velocity images, the initial conditions can be stated as

If the string is fixed at images, the displacement is zero and hence the boundary conditions will be

(8.31)equation

If the string is connected to a pin that is free to move in a transverse direction, the end will not be able to support any transverse force, and hence the boundary condition will be

If the axial force is constant and the end images is free, Eq. (8.32) becomes

(8.33)equation

If the end images of the string is connected to an elastic spring of stiffness k, the boundary condition will be

(8.34)equation

Some of the possible boundary conditions of a string are summarized in Table 8.1.

Table 8.1 Boundary conditions of a string.

Support conditions of the string Boundary conditions to be satisfied
1. Both ends fixed
Schematic diagram depicting a string with both ends fixed with P at l and O.
images
2. Both ends free
Schematic diagram depicting a string with both ends free with P above l and O.
images
3. Both ends attached with masses
Schematic diagram depicting a string with both ends attached with masses with P at m2 and m1.
images
4. Both ends attached with springs
Schematic diagram depicting a string with both ends attached with springs with P at k2 and k1.
images
5. Both ends attached with dampers
Schematic diagram depicting a string with both ends attached with dampers with P at c2 and c1.
images

8.4 FREE VIBRATION OF AN INFINITE STRING

Consider a string of infinite length. The free vibration equation of the string, Eq. (8.9), is solved using three different approaches in this section.

8.4.1 Traveling‐Wave Solution

The solution of the wave equation (8.9) can be expressed as

where images and images are arbitrary functions of images and images, respectively. The solution given by Eq. (8.35) is known as D'Alembert's solution. The validity of Eq. (8.35) can be established by differentiating Eq. (8.35) as

where a prime indicates a derivative with respect to the respective argument. By substituting Eqs. (8.36) and (8.37) into Eq. (8.9), we find that Eq. (8.9) is satisfied. The functions images and images denote waves that propagate in the positive and negative directions of the x axis, respectively, with a velocity c. The functions images and images can be determined from the known initial conditions of the string. Using the initial conditions of Eq. (8.30), Eq. (8.35) yields

where a prime in Eq. (8.39) denotes a derivative with respect to the respective argument at images (i.e. with respect to x). By integrating Eq. (8.39) with respect to x, we obtain

where images is a constant. Equations (8.38) and (8.40) can be solved to find images and images as

By replacing x by images and images, respectively, in Eqs. (8.41) and (8.42), we can express the wave solution of the string, images, as

The solution given by Eq. (8.43) can be rewritten as

(8.44)equation

where images represents a wave propagating due to a known initial displacement images with zero initial velocity, and images indicates a wave moving due to the initial velocity images with zero initial displacement. A typical wave traveling due to initial displacement (introduced by pulling the string slightly in the transverse direction with zero velocity) is shown in Fig. 8.2.

Schematic diagram depicting propagation of a wave caused by an initial displacement at t = t1 = 0; t = t2 > t1; t = t3 > t2; t = t4 > t3.

Figure 8.2 Propagation of a wave caused by an initial displacement.

8.4.2 Fourier Transform‐Based Solution

To find the free vibration response of an infinite string images under the initial conditions of Eq. (8.30), we take the Fourier transform of Eq. (8.9). For this, we multiply Eq. (8.9) by images and integrate from images to images:

Integration of the left‐hand side of Eq. (8.45) by parts results in

Assuming that both images and images tend to zero as images, the first term on the right‐hand side of Eq. (8.46) vanishes. Using Eq. (7.16), the Fourier transform of images is defined as

and Eq. (8.45) can be rewritten in the form

Note that the use of the Fourier transform reduced the partial differential equation (8.9) into the ordinary differentiation equation (8.48). The solution of Eq. (8.48) can be expressed as

where the constants images and images can be evaluated using the initial conditions, Eqs. (8.30). By taking the Fourier transforms of the initial displacement images and initial velocity images, we obtain

The use of Eqs. (8.50) and (8.51) in Eq. (8.49) leads to

(8.52)equation
(8.53)equation

whose solution gives

(8.54)equation
(8.55)equation

Thus, Eq. (8.49) can be expressed as

By using the inverse Fourier transform of Eq. (8.47), we obtain

(8.57)equation

which, in view of Eq. (8.56), becomes

Note that the inverse Fourier transforms of images and images, Eqs. (8.50) and (8.51), can be obtained as

(8.59)equation

so that

By integrating Eq. (8.60) with respect to images from images to images, we obtain

When Eqs. (8.61) and (8.62) are substituted into Eq. (8.58), we obtain

which can be seen to be identical to Eq. (8.43).

8.4.3 Laplace Transform‐Based Solution

The Laplace transforms of the terms in the governing equation (8.9) lead to

where

(8.66)equation

Using Eqs. (8.64) and (8.65) along with the initial conditions of Eq. (8.30), Eq. (8.9) can be expressed as

Now, we take the Fourier transform of Eq. (8.67). For this, we multiply Eq. (8.67) by images and integrate with respect to x from images to images, to obtain

The integral on the left‐hand side of Eq. (8.68) can be evaluated by parts:

Assuming that the deflection, images, and the slope, images, tend to be zero as images, Eq. (8.69) reduces to

(8.70)equation

and hence Eq. (8.68) can be rewritten as

equation

or

equation

or

(8.71)equation

where

(8.72)equation
(8.73)equation
(8.74)equation

Now we first take the inverse Fourier transform of images to obtain

and next we take the inverse Laplace transform of images to obtain

Noting that

(8.77)equation

and

(8.78)equation

Eqs. (8.76) and (8.75) yield

where

From Eqs. (8.80) and (8.81), we can write

(8.82)equation

In addition, the following identities are valid:

(8.84)equation
(8.85)equation

Thus, Eq. (8.79) can be rewritten as

(8.86)equation

which can be seen to be the same as the solution given by Eqs. (8.43) and (8.63). Note that Fourier transforms were used in addition to Laplace transforms in the current approach.

8.5 FREE VIBRATION OF A STRING OF FINITE LENGTH

The solution of the free vibration equation, Eq. (8.9), can be found using the method of separation of variables. In this method, the solution is written as

where images is a function of x only and images is a function of t only. By substituting Eq. (8.87) into Eq. (8.9), we obtain

Noting that the left‐hand side of Eq. (8.88) depends only on x while the right‐hand side depends only on t, their common value must be a constant, a, and hence

Equation (8.89) can be written as two separate equations:

The constant a is usually negative1 and hence, by setting images, Eqs. (8.90) and (8.91) can be rewritten as

The solution of Eqs. (8.92) and (8.93) can be expressed as

(8.95)equation

where images is the frequency of vibration, the constants A and B can be evaluated from the boundary conditions, and the constants C and D can be determined from the initial conditions of the string.

8.5.1 Free Vibration of a String with Both Ends Fixed

If the string is fixed at both ends, the boundary conditions are given by

Equations (8.96) and (8.94) yield

The condition of Eq. (8.97) requires that

in Eq. (8.94). Using Eqs. (8.98) and (8.99) in Eq. (8.94), we obtain

(8.100)equation

For a nontrivial solution, B cannot be zero and hence

Equation (8.101) is called the frequency or characteristic equation, and the values of ω that satisfy Eq. (8.101) are called the eigenvalues (or characteristic values or natural frequencies) of the string. The nth root of Eq. (8.101) is given by

(8.102)equation

and hence the nth natural frequency of vibration of the string is given by

(8.103)equation

The transverse displacement of the string, corresponding to images, known as the nth mode of vibration or nth harmonic or nth normal mode of the string is given by

(8.104)equation

In the nth mode, each point of the string vibrates with an amplitude proportional to the value of images at that point with a circular frequency images. The first four modes of vibration are shown in Fig. 8.3. The mode corresponding to images is called the fundamental mode, images is called the fundamental frequency, and

(8.105)equation
Schematic diagram depicting mode shapes of a string with the curve at points 0 and l forw1(x,t), l/2 for w2(x,t), l/3, 2l/3 for w3(x,t); l/4, l/2, 3l/4 for w4(x,t).

Figure 8.3 Mode shapes of a string.

is called the fundamental period. The points at which images for images are called nodes. It can be seen that the fundamental mode has two nodes (at images and images), the second mode has three nodes (at images, and images), and so on.

The free vibration of the string, which satisfies the boundary conditions of Eqs. (8.97) and (8.98), can be found by superposing all the natural modes images as

This equation represents the general solution of Eq. (8.9) and includes all possible vibrations of the string. The particular vibration that occurs is uniquely determined by the initial conditions specified. The initial conditions provide unique values of the constants images and images in Eq. (8.106). For the initial conditions stated in Eq. (8.30), Eq. (8.106) yields

Noting that Eqs. (8.107) and (8.108) denote Fourier sine series expansions of images and images in the interval images, the values of images and images can be determined by multiplying Eqs. (8.107) and (8.108) by images and integrating with respect to x from 0 to l. This gives the constants images and images as

Note that the solution given by Eq. (8.106) represents the method of mode superposition since the response is expressed as a superposition of the normal modes. As indicated earlier, the procedure is applicable in finding not only the free vibration response but also the forced vibration response of any continuous system.

Notes

  1. If images and images are both large, images and images and the frequency equation, Eq. (E8.3.10), reduces to

    Equation (E8.3.17) corresponds to the frequency equation of a wire with both ends fixed.

  2. If images and images are both small, images and images, and Eq. (E8.3.14) gives the frequencies as
    (E8.3.18)equation

    and Eq. (E8.3.16) yields the modal functions as

    (E8.3.19)equation

    It can be observed that this solution corresponds to that of a wire with both ends free.

  3. If images is large and images is small, images and images, and Eq. (E8.3.10) yields
    equation

    or

    (E8.3.20)equation

    and Eq. (E8.3.16) gives the modal functions as

    (E8.3.21)equation

    This solution corresponds to that of a wire which is fixed at images and free at images.

8.6 FORCED VIBRATION

The equation of motion governing the forced vibration of a uniform string subjected to a distributed load images per unit length is given by

Let the string be fixed at both ends so that the boundary conditions become

The solution of the homogeneous equation (with images in Eq. [8.111]), which represents free vibration, can be expressed as (see Eq. [8.106])

(8.114)equation

The solution of the nonhomogeneous equation (with images in Eq. [8.111]), which also satisfies the boundary conditions of Eqs. (8.112) and (8.113), can be assumed to be of the form

where images denotes the generalized coordinates. By substituting Eq. (8.115) into Eq. (8.111), we obtain

Multiplication of Eq. (8.116) by images and integration from 0 to l, along with the use of the orthogonality of the functions images, leads to

where

The solution of Eq. (8.117), including the homogeneous solution and the particular integral, can be expressed as

(8.119)equation

Thus, in view of Eq. (8.115), the forced vibration response of the string is given by

where the constants images and images are determined from the initial conditions of the string.

8.7 RECENT CONTRIBUTIONS

The D'Alembert's solution of Eq. (8.8), as given by Eq. (8.35), is obtained by assuming that the increase in tension due to stretching is negligible. If this assumption is not made, Eq. (8.9) becomes

where

(8.122)equation

with images denoting the density of the string. Here images denotes the speed of compressional longitudinal wave through the string. An approximate solution of Eq. (8.121) was presented by Bolwell [4]. The dynamics of cables, chains, taut inclined cables, and hanging cables was considered by Triantafyllou [5,6]. In particular, the problem of linear transverse vibration of an elastic string hanging freely under its own weight presents a paradox, in that a solution can be obtained only when the lower end is free. An explanation of the paradox was given by Triantafyllou [6], who also showed that the paradox can be removed by including bending stiffness using singular perturbations.

A mathematical model of the excitation of a vibrating system by a plucking action was studied by Griffel [7]. The mechanism is of the type used in musical instruments [8]. The effectiveness of the mechanism is computed over a range of the relevant parameters. In Ref. [9], Simpson derived the equations of in‐plane motion of an elastic catenary translating uniformly between its end supports in a Eulerian frame of reference. The approximate analytical solution of these equations is given for a shallow catenary in which the tension is dominated by the cable section modulus. Although the mathematical description of a vibrating string is given by the wave equation, a quantum model of information theory was used by Barrett to obtain a one‐degree‐of‐freedom mechanical system governed by a second‐order differential equation [10].

The vibration of a sectionally uniform string from an initial state was considered by Beddoe [11]. The problem was formulated in terms of reflections and transmissions of progressive waves and solved using the Laplace transform method without incorporating the orthogonality relationships. The exact equations of motion of a string were formulated by Narasimha [12], and a systematic procedure was described for obtaining approximations to the equations to any order, making only the assumption that the strain in the material of the string is small. It was shown that the lowest‐order equations in the scheme, which were nonlinear, were used to describe the response of the string near resonance.

Electrodischarge machining (EDM) is a noncontact process of electrically removing (cutting) material from conductive workpieces. In this process, a high potential difference is generated between a wire and a workpiece by charging them positively and negatively, respectively. The potential difference causes sparks between the wires and the workpiece. By moving the wire forward and sideways, the contour desired can be cut on the workpiece. In Ref. [13], Shahruz developed a mathematical model for the transverse vibration of the moving wire used in the EDM process in the form of a nonlinear partial differential equation. The equation was solved, and it was shown that the transverse vibration of the wire is stable and decays to zero for wire axial speeds below a critical value.

A comprehensive view of cable structures was presented by Irvine [14]. The natural frequencies and mode shapes of cables with attached masses have been determined by Sergev and Iwan [15]. The linear theory of free vibrations of a suspended cable has been outlined by Irvine and Caughey [16]. Yu presented explicit vibration solutions of a cable under complicated loads [17]. A theoretical and experimental analysis of free and forced vibration of sagged cable/mass suspension has been presented by Cheng and Perkins [18]. The linear dynamics of a translating string on an elastic foundation was considered by Perkins [19].

NOTE

  1. To show that a is usually a negative quantity, multiply Eq. (8.90) by images and integrate with respect to x from 0 to l to obtain

    Equation (a) indicates that the sign of a will be same as the sign of the integral on the left‐hand side. The left‐hand side of Eq. (a) can be integrated by parts to obtain

    The first term on the right‐hand side of Eq. (b) can be seen to be zero or negative for a string with any combination of fixed end images, free end images, or elastically supported end images, where k is the spring constant of the elastic support. Thus, the integral on the left‐hand side of Eq. (a), and hence the sign of a is negative.

REFERENCES

  1. 1 W. Nowacki, Dynamics of Elastic Systems, translated by H. Zorski, Wiley, New York, 1963.
  2. 2 N.W. McLachlan, Theory of Vibrations, Dover, New York, 1951.
  3. 3 S. Timoshenko, D.H. Young, and W. Weaver, Jr., Vibration Problems in Engineering, 4th ed., Wiley, New York, 1974.
  4. 4 J.E. Bolwell, The flexible string's neglected term, Journal of Sound and Vibration, Vol. 206, No. 4, pp. 618–623, 1997.
  5. 5 M.S. Triantafyllou, Dynamics of cables and chains, Shock and Vibration Digest, Vol. 19, pp. 3–5, 1987.
  6. 6 M.S. Triantafyllou and G.S. Triantafyllou, The paradox of the hanging string: an explanation using singular perturbations, Journal of Sound and Vibration, Vol. 148, No. 2, pp. 343–351, 1991.
  7. 7 D.H. Griffel, The dynamics of plucking, Journal of Sound and Vibration, Vol. 175, No. 3, pp. 289–297, 1994.
  8. 8 N.H. Fletcher and T.D. Rossing, The Physics of Musical Instruments, Springer‐Verlag, New York, 1991.
  9. 9 A. Simpson, On the oscillatory motions of translating elastic cables, Journal of Sound and Vibration, Vol. 20, No. 2, pp. 177–189, 1972.
  10. 10 T.W. Barrett, On vibrating strings and information theory, Journal of Sound and Vibration, Vol. 20, No. 3, pp. 407–412, 1972.
  11. 11 B. Beddoe, Vibration of a sectionally uniform string from an initial state, Journal of Sound and Vibration, Vol. 4, No. 2, pp. 215–223, 1966.
  12. 12 R. Narasimha, Non‐linear vibration of an elastic string, Journal of Sound and Vibration, Vol. 8, No. 1, pp. 134–146, 1968.
  13. 13 S.M. Shahruz, Vibration of wires used in electro‐discharge machining, Journal of Sound and Vibration, Vol. 266, No. 5, pp. 1109–1116, 2003.
  14. 14 H.M. Irvine, Cable Structures, MIT Press, Cambridge, MA, 1981.
  15. 15 S.S. Sergev and W.D. Iwan, The natural frequencies and mode shapes of cables with attached masses, Journal of Energy Resources Technology, Vol. 103, pp. 237–242, 1981.
  16. 16 H.M. Irvine and T.K. Caughey, The linear theory of free vibrations of a suspended cable, Proceedings of the Royal Society, London, Vol. A‐341, pp. 299–315, 1974.
  17. 17 P. Yu, Explicit vibration solutions of a cable under complicated loads, Journal of Applied Mechanics, Vol. 64, No. 4, pp. 957–964, 1997.
  18. 18 S.‐P. Cheng and N.C. Perkins, Theoretical and experimental analysis of the forced response of sagged cable/mass suspension, Journal of Applied Mechanics, Vol. 61, No. 4, pp. 944–948, 1994.
  19. 19 N.C. Perkins, Linear dynamics of a translating string on an elastic foundation, Journal of Vibration and Acoustics, Vol. 112, No. 1, pp. 2–7, 1990.

PROBLEMS

  1. 8.1 Find the free vibration response of a fixed–fixed string of length l which is given an initial displacement
    equation

    and initial velocity images.

  2. 8.2 A steel wire of diameter images. and length 3 ft is fixed at both ends and is subjected to a tension of 200 lb. Find the first four natural frequencies and the corresponding mode shapes of the wire.
  3. 8.3 Determine the stress that needs to be applied to the wire of Problem 8.2 to reduce its fundamental natural frequency of vibration by 50% of the value found in Problem 8.2.
  4. 8.4 A string of length l is fixed at images and subjected to a transverse force images at images. Find the resulting vibration of the string.
  5. 8.5 Find the forced vibration response of a fixed–fixed string of length l that is subjected to the distributed transverse force images.
  6. 8.6 A uniform string of length l is fixed at both ends and is subjected to the following initial conditions:
    equation

    Find the response of the string.

  7. 8.7 Derive the boundary conditions corresponding to support conditions 3, 4, and 5 of Table 8.1 from equilibrium considerations.
  8. 8.8 The transverse vibration of a string of length images is governed by the equation
    equation

    The boundary and initial conditions of the string are given by

    equation

    Find the displacement of the string, images.

  9. 8.9 A semi‐infinite string has one end at images and the other end at images. It is initially at rest on the x axis and the end images is made to oscillate with a transverse displacement of images. Find the transverse displacement of the string, images.
  10. 8.10 Find the natural frequencies of transverse vibration of a taut string of length l resting on linear springs of stiffnesses images and images at the ends images and images, respectively. Assume the following data: images, and images.
  11. 8.11 Find the traveling‐wave solution of an infinite string presented in Section 8.4.1 by solving the equation of motion
    equation

    with the initial conditions images and images by using Laplace transforms with respect to t and Fourier transforms with respect to x.

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