Solve exponential equations.
Solve logarithmic equations.
Equations with variables in the exponents, such as
are called exponential equations.
Sometimes, as is the case with the equation 25x=64, we can write each side as a power of the same number:
We can then set the exponents equal and solve:
We use the following property to solve exponential equations.
This property follows from the fact that for any a>0, a≠1, f(x)=ax is a one-to-one function. If ax=ay, then f(x)=f(y). Then since f is one-to-one, it follows that x=y. Conversely, if x=y, it follows that ax=ay, since we are raising a to the same power in each case.
Solve: 23x−7=32.
Now Try Exercise 7.
Another property that is used when solving some exponential equations and logarithmic equations is as follows.
This property follows from the fact that for any a>0, a≠1, f(x)=loga x is a one-to-one function. If loga x=loga y, then f(x)=f(y). Then since f is one-to-one, it follows that x=y. Conversely, if x=y, it follows that loga x=loga y, since we are taking the logarithm of the same number in each case.
When it does not seem possible to write each side as a power of the same base, we can use the property of logarithmic equality and take the logarithm with any base on each side and then use the power rule for logarithms.
Solve: 3x=20.
Now Try Exercise 11.
In Example 2, we took the common logarithm on both sides of the equation. Any base will give the same result. Let’s try base 3. We have
Note that we must change the base in order to do the final calculation.
Solve: 100e0.08t=2500.
Now Try Exercise 19.
Solve: 4x+3=3−x.
Now Try Exercise 21.
Solve: ex+e−x−6=0.
Now Try Exercise 25.
Equations containing variables in logarithmic expressions, such as log2 x=4 and log x+log (x+3)=1, are called logarithmic equations. To solve logarithmic equations algebraically, we first try to obtain a single logarithmic expression on one side and then write an equivalent exponential equation.
Solve: log3x=−2.
Now Try Exercise 33.
Solve: log x+log (x+3)=1.
Now Try Exercise 41.
Solve: log3 (2x−1)−log3 (x−4)=2.
Now Try Exercise 45.
Solve: ln (4x+6)−ln (x+5)=ln x.
Now Try Exercise 43.
Solve the exponential equation.
1. 3x=81
2. 2x=32
3. 22x=8
4. 37x=27
5. 2x=33
6. 2x=40
7. 54x−7=125
8. 43x−5=16
9. 27=35x·9x2
10. 3x2+4x=127
11. 84x=70
12. 28x=10−3x
13. 10−x=52x
14. 15x=30
15. e−c=52c
16. e4t=200
17. et=1000
18. e−t=0.04
19. e−0.03t=0.08
20. 1000e0.09t=5000
21. 3x=2x−1
22. 5x+2=41−x
23. (3.9)x=48
24. 250−(1.87)x=0
25. ex+e−x=5
26. ex−6e−x=1
27. 32x−1=5x
28. 2x+1=52x
29. 2ex=5−e−x
30. ex+e−x=4
Solve the logarithmic equation.
31. log5 x=4
32. log2 x=−3
33. log x=−4
34. log x=1
35. ln x=1
36. ln x=−2
37. log6414=x
38. log125125=x
39. log2 (10+3x)=5
40. log5 (8−7x)=3
41. log x+log (x−9)=1
42. log2 (x+1)+log2 (x−1)=3
43. log2 (x+20)−log2 (x+2)=log2 x
44. log (x+5)−log (x−3)=log 2
45. log8 (x+1)−log8 x=2
46. log x−log (x+3)=−1
47. log x+log (x+4)=log 12
48. log3(x+14)−log3(x+6)=log3 x
49. log (x+8)−log (x+1)=log 6
50. ln x−ln (x−4)= ln 3
51. log4 (x+3)+log4 (x−3)=2
52. ln (x+1)− ln x= ln 4
53. log (2x+1)−log (x−2)=1
54. log5 (x+4)+log5 (x−4)=2
55. ln (x+8)+ ln (x−1)=2 ln x
56. log3 x+log3 (x+1)=log3 2+log3 (x+3)
Solve.
57. log6 x=1−log6 (x−5)
58. 2x2−9x=1256
59. 9x−1=100(3x)
60. 2 ln x−ln 5= ln (x+10)
61. ex−2=−e−x
62. 2 log 50=3 log 25+log (x−2)
In Exercises 63–66:
Find the vertex.
Find the axis of symmetry.
Determine whether there is a maximum or a minimum value and find that value. [3.3]
63. g(x)=x2−6
64. f(x)=−x2+6x−8
65. G(x)=−2x2−4x−7
66. H(x)=3x2−12x+16
Solve using any method.
67. ex+e−xex−e−x=3
68. ln (ln x)=2
69. √ln x=ln√x
70. ln4√x=√ln x
71. (log3 x)2−log3x2=3
72. log3 (log4 x)=0
73. lnx2=(ln x)2
74. x(ln16)=ln 6
75. 52x−3·5x+2=0
76. xlog x=x3100
77. lnxln x=4
78. |2x2−8|=3
79. √(e2x·e−5x)−4ex÷e−x=e7
80. Given that a=(log125 5)log5 125, find the value of log3 a.
81. Given that a=log8 225 and b=log2 15, express a as a function of b.
82. Given that f(x)=ex−e−x, find f−1(x) if it exists.
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