10A Few Results on Fibonacci Cordial Labeling

U. M. Prajapati

St. Xavier’s College,
Ahmedabad, Gujarat (INDIA)
E-mail: [email protected]

K. K. Raval

Department of Mathematics,
Gujarat University,
Ahmedabad, Gujarat (INDIA)
E-mail: [email protected]

An injective function f: V(G) → {F0, F1, F2, …, Fn}, where Fj is the jth Fibonacci number is called Fibonacci cordial labeling if the induced function f*: E(G) → {0, 1} defined by f*(uv) = (f(u) + f(v)) (mod2) satisfies the condition that the total number of edges with label 1 and total number of edges with label 0 differ by at most 1. A graph which admits Fibonacci cordial labeling is called a Fibonacci cordial graph. We show that a comb graph and helm graph are Fibonacci cordial graphs. The cycle admits Fibonacci cordial labeling if and only if n ≡ 0, 1, 3 (mod 4) and n ≥ 3. A friendship graph is a Fibonacci cordial graph. Cn2 is a Fibonacci cordial graph if n is even and n ≥ 4.

10.1Introduction

We begin with simple, finite, undirected graph G, where V(G) and E(G) are the vertex set and edge set of G respectively. For all other terminology we follow Gross [4]. Now we provide a brief summary of definitions and other information which are necessary for the present investigations.

10.1.1Definition

Definition. The Fibonacci sequence can be defined by the linear recurrence relation satisfying:

Fn={0, if n=0;1 , if n=1;Fn1+Fn2, if n>1.

Definition. Let f: V(G) → {0, 1} for each edge uv assigned the label |f(u) − f(v)|, then f is said to be a cordial labeling [2] of G if the number of vertices with label 0 and the number of vertices with label 1 differ at most by 1, and the number of edges with label 0 and the number of edges with label 1 differ by at most 1.

Definition. An injective function f: V(G) → {F0, F1, F2, …, Fn}, where Fj is the jth Fibonacci number, is said to be Fibonacci cordial labeling [5] if the induced function f*: E(G) → {0, 1} defined by f*(uv) = (f(u) + f(v))(mod 2) satisfies the condition |ef(0) − ef(1)| ≤ 1, where ef(0) and ef(1) are the total number of edges with label 0 and 1 respectively. A graph which admits Fibonacci cordial labeling is called a Fibonacci cordial graph. It was first introduced by Rokad and Ghodasara in [6].

Karthikeyan et. al. showed that the wheel graph and bistar graph are Fibonacci cordial graphs [5].

We also note that Fn is even if and only if n ≡ 0 (mod 3).

Definition. The graph Wn = Cn + K1 is called a wheel graph [3]. The vertex corresponding to K1 is called the apex vertex and the vertices corresponding to Cn are called rim vertices.

Definition. The circulant graph [7] Cn(a1, a2, …, am) is the graph with vertex set {v1, v2, …, vm} and the edge set {vivi+aj,1in,1jm} where addition of indices in modulo n and m, n, a1, a2, …, am are positive integers such that 1ain2 and the ai’s are distinct. Cnk is the generalization of the circulant graphs Cn(1, 2, 3, …, k) given by Anholcer and Palmer [1].

In this chapter, we use the notation Cn2 for the circulant graph Cn(1, 2). Cn2 can also be considered as square of cycle graph Cn.

Definition. A helm graph [3] is obtained from the wheel graph Wn by adding a pendent edge on each rim vertex of the wheel.

Definition. The friendship graph [3] is one point union of C3 which is denoted by Fn=C3n, where n stands for the total number of C3.

10.2Main Results

Theorem 10.1

Cn is a Fibonacci cordial graph if and only if n ≡ 0, 1, 3 (mod 4) and n ≥ 3.

Proof.Case 1: n ≡ 0, 1, 3 (mod 4).

We label all the consecutive vertices of cycle Cn as v1, v2, v3, …, vn. Thus, |V(Cn)| = |E(Cn)| = n.

Sub case 1: n ≡ 1 (mod 6).

We define an injective function f: V(G) → {F0, F1, F2, …, Fn} such that, f(v1) = F0, f(v2) = F1, f(v3) = F2, f(v4) = F4, f(v5) = F3, f(v6) = F6 and f(v7) = F5 and for n > 7:

f(vn)={Fn1, if n2,3(mod6);Fn, if n0(mod6);Fn2, if n1(mod6);Fn, if n10(mod12);Fn2, if n11(mod12);Fn1, if n4,5(mod12).

Then ef(1)=n+12 and ef(0)=n12.

Sub case 2: n ≡ 8 (mod 12).

We define an injective function f: V(G) → {F0, F1, F2, …, Fn} such that, f(v1) = F0, f(v2) = F1 and for n > 2:

f(vn)={Fn1, if n2,3(mod6);Fn, if n0(mod6);Fn2, if n1(mod6);Fn, if n4(mod12);Fn2, if n5(mod12);Fn1, if n10,11(mod12).

Then ef(1)=n2 and ef(0)=n2.

Sub case 3: n ≡ 3 (mod 6).

We define an injective function f: V(G) → {F0, F1, F2, …, Fn} such that, f(v1) = F0, f(v2) = F1, f(v3) = F2 and for n > 3:

f(vn)={Fn, if n0(mod6);Fn2, if n1(mod6);Fn1, if n2,3(mod6);Fn1, if n10,11(mod12);Fn, if n4(mod12);Fn2, if n5(mod12).

Then ef(0)=n12 and ef(1)=n+12, for n = 3 and ef(1)=n12 and ef(0)=n+12, for n > 3.

Sub case 4: n ≡ 4 (mod 12).

We define an injective function f: V(G) → {F0, F1, F2, …, Fn} such that, f(v1) = F0, f(v2) = F3, f(v3) = F1, f(v4) = F2 and for n > 4:

f(vn)={Fn+2, if n1(mod6);Fn3, if n2(mod6);Fn2, if n3,4(mod6);Fn1, if n5(mod12);Fn+1, if n11(mod12);Fn, if n6(mod12);Fn2, if n0(mod12).

Then ef(0)=n2 and ef(1)=n2.

Sub case 5: n ≡ 5 (mod 6).

We define an injective function f: V(G) → {F0, F1, F2, …, Fn} such that, f(v1) = F0, f(v2) = F3, f(v3) = F1, f(v4) = F2, f(v5) = F4 and for n > 5:

f(vn)={Fn+1, if n2(mod6);Fn2, if n3,4(mod6);Fn1, if n5(mod6);Fn, if n6(mod12);Fn1, if n0,1(mod12);Fn2, if n7(mod12).

Then ef(0)=n+12 and ef(1)=n12, for n = 5 and ef(0)=n12 and ef(1)=n+12, for n > 5.

Sub case 6: n ≡ 0 (mod 12).

We define an injective function f: V(G) → {F0, F1, F2, …, Fn} such that,

f(vn)={Fn1, if n1,2,3,10,11(mod12);Fn, if n7,8,4(mod12);Fn3, if n9(mod12);Fn2, if n5(mod12);Fn1, if n0(mod6).

Then ef(1)=n2 and ef(0)=n2.

Thus, for all the above cases, |ef(0) − ef(1)| ≤ 1. Hence, Cn admits Fibonacci cordial labeling for n ≡ 0, 1, 3 (mod 4) and n ≥ 3.

Case 2: n ≡ 2 (mod 4). Hence, n = 4k + 2 for some positive integer k. Thus, |V(Cn)| = |E(Cn)| = 2(2k + 1). Clearly, to satisfy the condition of Fibonacci cordial labeling ef(0) = ef(1) = 2k + 1, which is an odd number. Suppose, we label the consecutive vertices of Cn with even Fibonacci numbers {F3i, 0 ≤ 3in} and the remaining vertices with odd Fibonacci numbers. In this case, ef(0) = 4k and ef(1) = 2. Now, if we interchange the labels of two vertices having odd and even Fibonacci numbers respectively then ef(0) = 4k − 2 and ef(1) = 4. Continuing in such a manner we obtain ef(0) = 2k + 2 and ef(1) = 2k. So ef(0) and ef(1) will always be even. Hence, |ef(0) − ef(1)| ≥ 2. So Cn is not a Fibonacci cordial graph for n ≡ 2 (mod 4).

Theorem 10.2

Cn2 is a Fibonacci cordial graph if n is even and n ≥ 4.

Proof. Let G=Cn2, we label all the consecutive vertices of the cycle Cn as v1, v2, v3, …, vn. Thus, |V(G)| = n and |E(G)| = 2n.

Case 1: n ≡ 0 (mod 6).

We define an injective function f: V(G) → {F0, F1, F2, …, Fn} such that,

f(vn)={Fn1, if n1,2,5,0(mod6);Fn, if n3(mod6);Fn2, if n4(mod6).

Thus, ef(1) = ef(0) = n.

Case 2: n ≡ 2 (mod 6).

We define an injective function f: V(G) → {F0, F1, F2, …, Fn} such that, f(v1) = F0, f(v2) = F1, f(v3) = F3 and for n > 3:

f(vn)={Fn1, if n2(mod6);Fn+1, if n5(mod6);Fn, if n3(mod6);Fn2, if n0,1,4(mod6).

Thus, ef(1) = ef(0) = n.

Case 3: n ≡ 4 (mod 6).

We define an injective function f: V(G) → {F0, F1, F2, …, Fn} such that, f(v1) = F0, f(v2) = F1, f(v3) = F3 and for n > 3:

f(vn)={Fn2, if n0,4,3(mod6);Fn+1, if n5(mod6);Fn+2, if n1(mod6);Fn3, if n2(mod6).

Thus ef(1) = ef(0) = n.

Thus, from all the above cases, |ef(0) − ef(1)| ≤ 1. Hence, Cn2 admits Fibonacci cordial labeling.

Theorem 10.3

Comb graph PnK1 is a Fibonacci cordial graph.

Proof. We label all the consecutive vertices of the path Pn in G=PnK1 as v1, v2, v3, …, vn, vn+1. We label all the vertices as {ui, 1 ≤ in + 1} corresponding to each of the vertices {vi, 1 ≤ in + 1}. Clearly, |V(G)| = 2n + 2 and |E(G)| = 2n + 1.

In all the below cases let S be a set of unlabeled vertices and g be an injective function form S to F3i+1, F3i+2, 0 ≤ 3i + 1, 3i + 2 ≤ 2n + 2.

Case 1: 1 ≤ n ≤ 6.

Sub case 1: n is odd.

We define an injective function f: V(G) → {F0, F1, F2, …, F2n+2} such that,

f(x)={F3i, if x=vi+1,i=0,1,2,,n+12;g(x), if xS.

Sub case 2: n = 2.

We define an injective function f: V(G) → {F0, F1, F2, …, F2n+2} such that,

f(x)={F3i, if x=vi+1,i=0,1;g(x), if xS.

Sub case 3: n = 4, 6.

We define an injective function f: V(G) → {F0, F1, F2, …, F2n+2} such that,

f(x)={F3i, if x=vi+1,i=0,1,2,,n2+1;g(x), if xS.

Case 2: n > 6.

Sub case 1: n ≡ 1 (mod 6).

We define an injective function f: V(G) → {F0, F1, F2, …, F2n+2} such that,

f(x)={F3(i1), if x=v2i1,i=1,2,,n6;F3n6+3i, if x=uni+1,i=0,1,2,,n+12;g(x), if xS.

Sub case 2: n ≡ 2 (mod 6).

We define an injective function f: V(G) → {F0, F1, F2, …, F2n+2} such that,

f(x)={F3(i1), if x=v2i1,i=1,2,,n6;F3(n6+3i), if x=uni+1,i=0,1,2,,n22;g(x), if xS.

Sub case 3: n ≡ 3, 5 (mod 6).

We define an injective function f: V(G) → {F0, F1, F2, …, F2n+2} such that,

f(x)={F3(i1), if x=v2i1,i=1,2,,n6;F3(n6+3i), if x=uni+1,i=0,1,2,,n12;g(x), if xS.

Sub case 4: n ≡ 0, 4 (mod 6).

We define an injective function f: V(G) → {F0, F1, F2, …, F2n+2} such that,

f(x)={F3(i1), if x=v2i1,i=1,2,,n6;F3(n6)+3i, if x=uni+1,i=0,1,2,,n2;g(x), if xS.

Thus, for all the above cases |ef(0) − ef(1)| ≤ 1. Hence, the comb graph is Fibonacci cordial graph.

Theorem 10.4

A helm graph is a Fibonacci cordial graph.

Proof. We label the apex vertex as v0 and all the consecutive vertices of the cycle Cn in Hn as v1, v2, v3, …, vn. We label all the vertices as {wi, 1 ≤ in} corresponding to each of the vertices {vi, 1 ≤ in}. Clearly, |V(Hn)| = 2n + 1 and |E(Hn)| = 3n.

Case 1: n ≡ 1 (mod 6).

Let g be any injection from the set S={v1,v2,,vn32}{vn+12,vn+32,,vn} {wn+12,wn+32,,wn} to the set {F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=wi,i=1,2,3,,n12;F3(i+1), if x=vi,i=n12+k,k=0,1,2,,n61;g(x), if xS.

Then ef(0)=3n2 and ef(1)=3n2.

Case 2: n ≡ 3, 5 (mod 6).

Let g be any bijection from the set S={v1,v2,,vn32}{vn+12,vn+32,,vn}{wn+12,wn+32,,wn} to the set {F3i+1,F3i+2,i=0,1,2,,2n+13}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=wi,i=1,2,3,,n12;F3(i+1), if x=vi,i=n12+k,k=0,1,2,,n6;g(x), if xS.

Then ef(0)=3n2 and ef(1)=3n2.

Case 3: n ≡ 0, 2, 4 (mod 6).

Sub case 1: n = 4.

Let g be an injection from the set S={v1,v3,v4}{w2,w3,w4} to the set {F1, F2, F4, F5, F7, F8, F9}. We define an injective function f: V(G) → {F0, F1, F2, …, F8} such that,

f(vn)={F0, if x=v0;F3, if x=w1;F6, if x=v2;g(x), if xS.

Then ef(1) = ef(0) = 6.

Sub case 2: n ≥ 6.

Let g be an injection from the set S={vn2+n6,vn2+n6+1,,vn} {v1,v2,,vn21} {wn2+1,wn2+2,,wn} to the set {F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=wi,i=1,2,3,,n2;F3(i+1), if x=vi,i=n2+k,k=0,1,2,,n61;g(x), if xS.

Then ef(1)=ef(0)=3n2.

Thus, from all the above cases |ef(0) − ef(1)| ≤ 1. Hence, Hn admits Fibonacci cordial labeling. Hn is a Fibonacci cordial graph.

Theorem 10.16

A friendship graph is a Fibonacci cordial graph.

Proof. A friendship graph is one point union of C3 which is denoted by Fn=C3n, where n stands for the total number of C3. We label the center vertex as v0. All other vertices are labeled with {vi, i = 1, 2, 3, …, 2n} consecutively. Thus, |V(Fn)| = 2n + 1 and |E(Fn)| = 3n.

Case 1: n ≡ 1 (mod 6).

Sub case 1: n = 1.

We define an injective function f: V(G) → {F0, F1, F2} such that, f(v0) = F0, f(v1) = F1, f(v2) = F2. Thus, ef(0) = 1 and ef(1) = 2.

Sub case 2: n ≡ 1 (mod 12) and n > 1.

Let g be a injection from the set S={vi,i=n+32+2k,k=0,1,2,,3(n1)4} {vi,i=5n+16+2k,k=0,1,2,,7(n1)12} to the set

{F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3,,n12;F3(n+2k+1)2, if x=vi,i=n+12+2k,k=0,1,2,,n76;g(x), if xS.

By the above induced labeling we obtain, ef(0)=3n2 and ef(1)=3n2.

Sub case 3: n = 7.

Let g be an injection from the set S = {vi, i = 5, 6, …, 14} to the set {F3i+1, F3i+2, i = 0, 1, 2, 3, 4}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3,,n+12;g(x), if xS.

By the above induced labeling we obtain, ef(1) = 10 and ef(0) = 11.

Sub case 4: n ≡ 7 (mod 12) and n > 7.

Let g be an injection from the set S={vi,i=n72+2k,k=0,1,2,,3n54} {vi,i=5(n1)6+2k,k=0,1,2,,7n112} to the set {F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, Fn−1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3,,n+12;F3(n+2k+3)2, if x=vi,i=n+32+2k,k=0,1,2,,n136;g(x), if xS.

By the above induced labeling we obtain, ef(1)=3n2 and ef(0)=3n2.

Case 2: n ≡ 0 (mod 12).

Let g be an injection from the set S={vi,i=n+42+2k,k=0,1,2,,3n44} {vi,i=5n+66+2k,k=0,1,2,,7n1212} to the set {F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3,,n2;F3(n+2k+2)2, if x=vi,i=n+22+2k,k=0,1,2,,n66;g(x), if xS.

By the above induced labeling we obtain, ef(1)=ef(0)=3n2.

Case 3: n ≡ 8 (mod 12).

Let g be an injection from the set S={vi,i=n+42+2k,k=0,1,2,,3n44} {vi,i=5n+26+2k,k=0,1,2,,7n812} to the set {F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3,,n2;F3(n+2k+2)2, if x=vi,i=n+22+2k,k=0,1,2,,n86;g(x), if xS.

By the above induced labeling we obtain, ef(1)=ef(0)=3n2.

Case 4: n ≡ 3( mod 6).

Sub case 1: n = 3.

Let g be an injection from the set S = {vi, i = 3, 4, 5, 6} to the set {F3i+1, F3i+2, i = 0, 1}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2;g(x), if xS.

By the above induced labeling we obtain, ef(1) = 4 and ef(0) = 5.

Sub case 2: n ≡ 3 (mod 12) and n > 3.

Let g be an injection from the set S={vi,i=n+52+2k,k=0,1,2,,3n54} {vi,i=5n+36+2k,k=0,1,2,,7n912} to the set {F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, Fn−1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3,,n2;F3(n+2k+3)2, if x=vi,i=n+32+2k,k=0,1,2,,n61;g(x), if xS.

By the above induced labeling we obtain, ef(1)=3n2 and ef(0)=3n2.

Sub case 3: n ≡ 9 (mod 12).

Let g be an injection from the set S={vi,i=5n96+2k,k=0,1,2,,7n+912} {vi,i=5n+96+2k,k=0,1,2,,7n1512} to the set {F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3,,n2;F3(n+2k+1)2, if x=vi,i=n+12+2k,k=0,1,2,,n6;g(x), if xS.

By the above induced labeling we obtain, ef(0)=3n2 and ef(1)=3n2.

Case 5: n ≡ 4 (mod 6).

Sub case 1: n = 4.

Let g be an injection from the set S = {vi, i = 3, 4, …, 8} to the set

{F3i+1, F3i+2, i = 0, 1, 2}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2;g(x), if xS.

By the above induced labeling we obtain, ef(1) = ef(0) = 6. Thus, |ef(0) − ef(1)| ≤ 1.

Sub case 2: n > 4.

Let g be an injection from the set S={vi,i=n+42+2k,k=0,1,2,,3n44} {vi,i=5n26+2k,k=0,1,2,,n106} to the set

{F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3,,n2;F3(n+2k+2)2, if x=vi,i=n+22+2k,k=0,1,2,,n106;g(x), if xS.

By the above induced labeling we obtain, ef(1)=ef(0)=3n2.

Case 6: n ≡ 5 (mod 6).

Sub case 1: n = 5.

Let g be an injection from the set S={vi,i=4,5,,10} to the set

{F3i+1,i=0,1,2,3}{F3i+2,i=0,1,2}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3;g(x), if xS.

By the above induced labeling we obtain, ef(1) = 8 and ef(0) = 7.

Sub case 2: n ≡ 5 (mod 12) and n > 5.

Let g be an injection from the set S={vi,i=n+32+2k,k=0,1,2,,3n34} {vi,i=5n+56+2k,k=0,1,2,,7n1112} to the set

{F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3,,n+12;F3n+6k+92, if x=vi,i=n+52+2k,k=0,1,2,,n116;g(x), if xS.

By the above induced labeling we obtain, ef(0)=3n2 and ef(1)=3n2.

Sub case 3: n ≡ 11 (mod 12).

Let g be an injection from the set S={vi,i=n+52+2k,k=0,1,2,,3n54} {vi,i=5n16+2k,k=0,1,2,,7n512} to the set {F3i+1,F3i+2,i=0,1,2,,[2n+13]}. We define an injective function f: V(G) → {F0, F1, F2, …, F2n+1} such that,

f(vn)={F0, if x=v0;F3i, if x=vi,i=1,2,3,,n+12;F3(n+2k+3)2, if x=vi,i=n+32+2k,k=0,1,2,,n116;g(x), if xS.

By the above induced labeling we obtain, ef(1)=3n2 and ef(0)=3n2.

Thus, by all the above cases |ef(0) − ef(1)| ≤ 1. Hence, Fn is a Fibonacci cordial graph.

10.3Conclusion

We conclude that a cycle admits Fibonacci cordial labeling if and only if n ≥ 3 and n ≡ 0, 1, 3 (mod 4). Some other graphs like the comb graph, helm graph and friendship graph are also Fibonacci cordial graphs. Cn2 is a Fibonacci cordial graph if n is even and n ≥ 4. For the future, one can explore more Fibonacci cordial graph families. Also, different patterns of labeling can be discovered such that the graph admits Fibonacci cordial labeling.

References

1.M. Anholcer and C. Palmer. Irregular labelings of circulant graphs. Discrete Mathematics, 312(23): 3461-3466, 2012.

2.I. Cahit. Cordial graphs: A weaker version of graceful and harmonious graphs. Ars Combinatoric, 23, 201-207, 2018.

3.J. A. Gallian. A dynamic survey of graph labeling. The Electronic Journal of Combinatorics, #DS6, 2018.

4.J. Gross and J. Yellen. Handbook of Graph Theory, CRC Press, 2004.

5.C. Karthikeyan, M. Abinaya, S. Arthi, V. Surya and K. V. Sreelakshmi. Fibonacci cordial labeling of some special graphs. International Journal for Scientific Research and Development, 5(12): 348-350, 2018.

6.A. H. Rokad and G. V. Ghodasara. Fibonacci cordial labeling of some special graphs. Annals of Pure and Applied Mathematics, 11(1): 133-144, 2016.

7.A. Semaničová. On magic and supermagic circulant graphs. Discrete Mathematics, 306, 2263-2269, 2006.

..................Content has been hidden....................

You can't read the all page of ebook, please click here login for view all page.
Reset
3.133.12.172