5
Structure Systems

5.1 Introduction

The complex situation of wave propagation in structures becomes even worse for closed structural systems. When specific features like holes, rigs, beading or any complicated shape is given, this is definitely the world of numerical methods. Current finite element methods (FEM) in combination with pre and post processors can handle very complex and large systems as for example trains or aircraft. But, the modelling procedure, the creation of the mesh, and the population of the property and material database are time consuming. Analogous to fluid systems we stay with academic cases to work out the full frequency range.

Even though we are not dealing with the details of FEM we will rely on the discrete representation of systems as introduced in section 1.4. Some of the following treatments rely on the discrete matrix formulation of structures, that is the dynamic stiffness matrix. Thus, the principle definitions are given without description of the finite element method. Please rely for example on the textbook from Bathe (1982) for more details. In Chapter 3 the equations of motion are expressed in displacements u,v,w, the components of the stress tensor for the bulk material σij and forces and moments Fi,Mi. Rotations βi are approximated as the derivative of displacement components.

In finite element theory the rotational components are considered as dedicated degrees of freedom. Thus, in this chapter the natural coordinates will therefore be the displacements u,v,w, the rotations βx,βy,βz and the according forces Fx,Fy,Fz, and moments Mx,My,Mz.

Consequently all discrete structural subsystems are described using a dynamic stiffness matrix of the form:

Start 4 By 4 Matrix 1st Row 1st Column bold-italic upper D 11 2nd Column bold-italic upper D 12 3rd Column midline-horizontal-ellipsis 4th Column bold-italic upper D Subscript 1 upper N Baseline 2nd Row 1st Column bold-italic upper D 21 2nd Column bold-italic upper D 22 3rd Column midline-horizontal-ellipsis 4th Column bold-italic upper D Subscript 2 upper N Baseline 3rd Row 1st Column vertical-ellipsis 2nd Column vertical-ellipsis 3rd Column vertical-ellipsis 4th Column vertical-ellipsis 4th Row 1st Column bold-italic upper D Subscript upper N Baseline 1 Baseline 2nd Column bold-italic upper D Subscript upper N Baseline 2 Baseline 3rd Column midline-horizontal-ellipsis 4th Column bold-italic upper D Subscript upper N upper N Baseline EndMatrix Start 4 By 1 Matrix 1st Row bold-italic q 1 2nd Row bold-italic q 2 3rd Row midline-horizontal-ellipsis 4th Row bold-italic q Subscript upper N Baseline EndMatrix equals Start 4 By 1 Matrix 1st Row bold-italic upper F 1 2nd Row bold-italic upper F 2 3rd Row vertical-ellipsis 4th Row bold-italic upper F Subscript upper N Baseline EndMatrix equals Start 1 By 1 Matrix 1st Row bold-italic upper D EndMatrix Start 1 By 1 Matrix 1st Row bold-italic q EndMatrix equals Start 1 By 1 Matrix 1st Row bold-italic upper F EndMatrix  (5.1)

{q} is the vector of generalised displacement degrees of freedom including rotations. The vector is called generalised because the displacement can be represented in any base coordinate system, for example modal coordinates, wavelets or wavenumber. Consequently, {F} is the generalised force vector including forces and moments of the accompanying displacements.

Due to the fact that the displacement is the natural degree of freedom we switch from the impedance to the dynamic stiffness concept. In the complex notation we may easily change between velocity and displacement using the jω factor for the derivative.

StartLayout 1st Row 1st Column bold-italic v Subscript x 2nd Column equals j omega bold-italic u 3rd Column bold-italic upper D equals j omega bold-italic upper Z EndLayout

However, even if structure systems are very complicated it is necessary to elaborate some solutions for representative systems in order to be prepared for random methods, and the modal density is one of those quantities where analytical solutions yield results for the full frequency range that can later be used for a class of random systems.

5.2 One-dimensional Systems

5.2.1 Longitudinal Waves in Finite Beams

Figure 5.1 Finite beam with boundary conditions as two-port system.

Rods are beams without bending capabilities or with exclusive treatment of dilatation of longitudinal waves. Thus, the solution is similar to the propagation of fluid waves in one-dimensional systems but with different physical quantities. We solve the equation

StartLayout 1st Row with Label left-parenthesis reverse-solidus text left-brace 3.77 right-brace right-parenthesis EndLabel StartFraction partial-differential squared bold-italic u Over partial-differential x squared EndFraction plus StartFraction 1 Over k Subscript upper L upper B Baseline EndFraction bold-italic u equals 0 with k Subscript upper L upper B Baseline equals StartRoot StartFraction omega squared rho 0 Over upper E EndFraction EndRoot EndLayout  (3.77)

for the given boundary conditions. Using the solution of the one dimensional wave Equation (3.78) and relationship (3.81)

table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell bold italic u left parenthesis x right parenthesis end cell cell equals bold italic A e to the power of negative j k x end exponent plus bold italic B e to the power of plus j k x end exponent end cell end table  (5.2)
table attributes columnalign right left columnspacing 0em 2em end attributes row cell bold italic sigma subscript 1 left parenthesis x right parenthesis end cell cell blank equals j omega z subscript L B end subscript left parenthesis negative bold italic A e to the power of negative j k x end exponent plus bold italic B e to the power of plus j k x end exponent right parenthesis end cell end table  (5.3)

With the following boundaries regarding the connections at both ends expressed in discrete degrees of freedom

StartLayout 1st Row 1st Column bold u left-parenthesis 0 right-parenthesis equals bold u 1 2nd Column bold u left-parenthesis upper L right-parenthesis equals bold u 2 EndLayout  (5.4a)
StartLayout 1st Row 1st Column bold sigma 1 left-parenthesis 0 right-parenthesis equals minus StartFraction bold upper F 1 Over upper A EndFraction 2nd Column sigma 1 left-parenthesis upper L right-parenthesis equals StartFraction upper F 2 Over upper A EndFraction EndLayout  (5.4b)

Comparing the above Equations to (4.1) and (4.2) we see that all solutions are provided by section 4.1 when we exchange the following variables:

StartLayout 1st Row 1st Column bold-italic p 2nd Column bold-italic u 3rd Column bold-italic v Subscript x 4th Column minus bold-italic sigma 1 5th Column 1 slash z 0 6th Column equals j omega z Subscript upper L upper B EndLayout  (5.5)

This leads to the dynamic stiffness matrix for the rod

StartLayout 1st Row 1st Column j omega upper A z Subscript upper L upper B Baseline Start 2 By 2 Matrix 1st Row 1st Column StartFraction 1 Over j tangent left-parenthesis bold-italic k upper L right-parenthesis EndFraction 2nd Column minus StartFraction 1 Over j sine left-parenthesis bold-italic k upper L right-parenthesis EndFraction 2nd Row 1st Column minus StartFraction 1 Over j sine left-parenthesis bold-italic k upper L right-parenthesis EndFraction 2nd Column StartFraction 1 Over j tangent left-parenthesis bold-italic k upper L right-parenthesis EndFraction EndMatrix StartBinomialOrMatrix bold-italic u 1 Choose bold-italic u 2 EndBinomialOrMatrix 2nd Column equals upper A upper E k Subscript upper L upper B Baseline 2nd Row 1st Column Start 2 By 2 Matrix 1st Row 1st Column StartFraction 1 Over tangent left-parenthesis bold-italic k upper L right-parenthesis EndFraction 2nd Column minus StartFraction 1 Over sine left-parenthesis bold-italic k upper L right-parenthesis EndFraction 2nd Row 1st Column minus StartFraction 1 Over sine left-parenthesis bold-italic k Subscript right-parenthesis Baseline EndFraction 2nd Column StartFraction 1 Over tangent left-parenthesis bold-italic k upper L right-parenthesis EndFraction EndMatrix StartBinomialOrMatrix bold-italic u 1 Choose bold-italic u 2 EndBinomialOrMatrix 2nd Column equals StartBinomialOrMatrix bold-italic upper F 1 Choose bold-italic upper F 2 EndBinomialOrMatrix EndLayout  (5.6)

It is worth mentioning that for k1 all denominators are approximately sin(kL)kL and hence

limit Underscript k right-arrow 0 Endscripts Start 1 By 1 Matrix 1st Row bold-italic upper D EndMatrix Subscript bar Baseline equals StartFraction upper E upper A Over upper L EndFraction Start 2 By 2 Matrix 1st Row 1st Column 1 2nd Column negative 1 2nd Row 1st Column negative 1 2nd Column 1 EndMatrix equals Start 2 By 2 Matrix 1st Row 1st Column k Subscript s Baseline 2nd Column minus k Subscript s Baseline 2nd Row 1st Column minus k Subscript s Baseline 2nd Column k Subscript s Baseline EndMatrix with k Subscript s Baseline equals upper E upper A slash upper L  (5.7)

with ks being the stiffness constant of the spring realised by a rod – it is the same as (1.95). The matrix can be used in a mechanical network representation. All expressions derived for power and impedance can also be used. For example the mechanical input impedance of a rod at port one and with a given mechanical impedance Z=Fx/v at port two after some lengthy exchange operations is

bold-italic upper Z 1 equals StartFraction bold-italic upper F 1 Over j omega bold-italic u 1 EndFraction equals upper A z Subscript upper L upper B Baseline StartFraction bold-italic upper Z 2 cosine left-parenthesis bold-italic k upper L right-parenthesis plus j upper A z Subscript upper L upper B Baseline sine left-parenthesis bold-italic k upper L right-parenthesis Over upper A z Subscript upper L upper B Baseline cosine left-parenthesis bold-italic k upper L right-parenthesis plus j bold-italic upper Z 2 sine left-parenthesis bold-italic k upper L right-parenthesis EndFraction  (5.8)

All considerations regarding system response, power input, etc. are also equivalent to section 4.1.

5.2.1.1 Modes

The expressions for the mode shapes can be derived using the same variable exchange from (5.5). The modes can be fixed or free. In technical systems, beams and plates are fixed at the ends, and an excitation is only possible for free DOFs. The normalized mode shapes for fixed boundaries (u(0)=0,u(L)=0) are

normal upper Phi left-parenthesis x right-parenthesis Subscript u comma n Baseline equals StartRoot StartFraction epsilon Subscript n Baseline Over upper L EndFraction EndRoot sine left-parenthesis k Subscript n Baseline x right-parenthesis with epsilon Subscript n Baseline equals StartLayout Enlarged left-brace 1st Row 1st Column 1 2nd Column for n equals 0 2nd Row 1st Column 2 2nd Column for n greater-than 0 EndLayout  (5.9)

or for free boundaries (σ(0)=0,σ(L)=0)

normal upper Phi left-parenthesis x right-parenthesis Subscript u comma n Baseline equals StartRoot StartFraction epsilon Subscript n Baseline Over upper L EndFraction EndRoot cosine left-parenthesis k Subscript n Baseline x right-parenthesis with epsilon Subscript n Baseline equals StartLayout Enlarged left-brace 1st Row 1st Column 1 2nd Column for n equals 0 2nd Row 1st Column 2 2nd Column for n greater-than 0 EndLayout  (5.10)

both with the modal wavenumbers kn=nπL. The free modes allow for excitation on both ends, the fixed modes only at inner DOFs. Entering the modes into the harmonic inhomogeneous wave equation for longitudinal waves (3.77)

rho 0 upper A left-parenthesis StartFraction partial-differential squared bold-italic u Over partial-differential x squared EndFraction plus bold-italic k Subscript upper L upper B Baseline bold-italic u right-parenthesis equals upper F prime left-parenthesis x right-parenthesis  (5.11)

and writing the force density per length expression with the use of the delta function

upper F left-parenthesis x 0 right-parenthesis equals integral Subscript negative normal infinity Superscript normal infinity Baseline bold-italic upper F delta left-parenthesis x minus x 0 right-parenthesis d x

yields the response shape

bold-italic u left-parenthesis x right-parenthesis equals sigma-summation Underscript n equals 0 Overscript normal infinity Endscripts bold-italic u prime Subscript n Baseline normal upper Phi Subscript u comma n  (5.12)

The modal coordinates un are derived by entering this into (5.11) and using the orthogonality of the shape functions providing

bold-italic u prime Subscript n Baseline equals StartFraction normal upper Phi Subscript u comma n Baseline bold-italic f left-parenthesis x right-parenthesis Over rho 0 upper A left-parenthesis k Subscript n Superscript 2 Baseline minus bold-italic k squared right-parenthesis EndFraction  (5.13)

Obviously, the modal density is equal to the pipe solution as it depends only on cLB and L.

StartLayout 1st Row 1st Column upper N 2nd Column equals StartFraction upper L omega Over pi c Subscript upper L upper B Baseline EndFraction 3rd Column n left-parenthesis omega right-parenthesis 4th Column equals StartFraction upper L Over pi c Subscript upper L upper B Baseline EndFraction EndLayout

5.2.2 Bending wave in Finite Beams

In beams, bending waves can propagate with elongation to the direction of the main axes. We skip the analytical closed solution for bending wave motion and stay with the modal shape description for the calculation of bending motion response.

5.2.2.1 Modes

We choose bending motion around the y-axis with displacement w in the z-direction. The boundary conditions are

StartLayout 1st Row 1st Column w left-parenthesis 0 right-parenthesis equals 0 2nd Column w left-parenthesis upper L right-parenthesis equals 0 EndLayout  (5.41a)
StartLayout 1st Row 1st Column upper M Subscript y Baseline left-parenthesis 0 right-parenthesis equals minus upper B Subscript y Baseline StartFraction partial-differential squared w Over partial-differential x squared EndFraction left-parenthesis 0 right-parenthesis 2nd Column upper M Subscript y Baseline EndLayout left-parenthesis upper L right-parenthesis equals minus upper B Subscript y Baseline StartFraction partial-differential squared w Over partial-differential x squared EndFraction left-parenthesis upper L right-parenthesis equals 0  (5.41b)

When entering these conditions into the global solution (3.107)

bold-italic w left-parenthesis x comma omega right-parenthesis equals bold-italic w 1 e Superscript j k Super Subscript upper B Superscript x Baseline plus bold-italic w 2 e Superscript minus j k Super Subscript upper B Superscript x Baseline plus bold-italic w Subscript 1 upper D Baseline e Superscript k Super Subscript upper B Superscript x Baseline plus bold-italic w Subscript 2 upper D Baseline e Superscript minus k Super Subscript upper B Superscript x

this leads to w1=w2 and w1D=w2D=0. Thus, the mode shape function is

normal upper Phi left-parenthesis x right-parenthesis Subscript w comma n Baseline equals StartRoot StartFraction epsilon Subscript n Baseline Over upper L EndFraction EndRoot sine left-parenthesis k Subscript n Baseline x right-parenthesis with epsilon Subscript n Baseline equals StartLayout Enlarged left-brace 1st Row 1st Column 1 2nd Column for n equals 0 2nd Row 1st Column 2 2nd Column for n greater-than 0 EndLayout  (5.15)

with kn=nπ/L. There are also free modes; the solution is a combination of cosine and hyperbolic cosine functions, however, because coefficients w1D and w2D are not vanishing in that case. The modal wavenumber is similar to the known one-dimensional formulas, but there is a difference for the modal frequency

omega Subscript n Baseline equals left-parenthesis StartFraction n pi Over upper L EndFraction right-parenthesis squared StartRoot StartFraction upper B Subscript y Baseline Over m prime EndFraction EndRoot  (5.16)

The distance between each modal frequency is not constant. So, it is convenient to use the constant wavenumber count of modes that are below k

upper N left-parenthesis k right-parenthesis equals StartFraction k upper L Over pi EndFraction  (5.17)

With this equation we can derive the modal density by applying the chain rule

n Subscript 1 upper D Baseline left-parenthesis omega right-parenthesis equals StartFraction d upper N Over d omega EndFraction equals StartFraction d upper N Over d k EndFraction StartFraction d k Over d omega EndFraction equals StartFraction upper L Over pi c Subscript gr Baseline EndFraction equals StartFraction upper L Over 2 pi c Subscript upper B Baseline EndFraction equals StartFraction upper L Over 2 pi EndFraction RootIndex 4 StartRoot StartFraction m prime omega squared Over upper B Subscript y Baseline EndFraction EndRoot  (5.18)

This is the same formula as (4.41) but with the group velocity.

5.2.2.2 Modal Response

The displacement in the z-direction in modal coordinates is given by

bold-italic w left-parenthesis x right-parenthesis equals sigma-summation Underscript n equals 1 Overscript normal infinity Endscripts bold-italic w prime Subscript n Baseline normal upper Phi left-parenthesis x right-parenthesis Subscript w comma n  (5.19)

Entering this into the inhomogeneous form of (3.104a)

minus omega squared m prime bold-italic w plus upper B Subscript y Baseline StartFraction partial-differential Superscript 4 Baseline bold-italic w Over partial-differential x Superscript 4 Baseline EndFraction equals bold-italic upper F prime Subscript z  (5.20)

gives for the force distribution

sigma-summation Underscript n equals 1 Overscript normal infinity Endscripts m prime left-parenthesis omega Subscript n Superscript 2 Baseline minus omega squared right-parenthesis bold-italic w prime Subscript n Baseline normal upper Phi Subscript w comma n Baseline equals bold-italic upper F prime Subscript z Baseline left-parenthesis x right-parenthesis  (5.21)

Multiplication from the right with Φw,m* and integration along the beam gives

bold-italic w prime Subscript m Baseline equals integral Subscript 0 Superscript upper L Baseline StartFraction normal upper Phi Subscript w comma m Superscript asterisk Baseline bold-italic upper F prime Subscript z Baseline left-parenthesis x right-parenthesis Over m prime left-parenthesis omega squared minus omega Subscript m Superscript 2 Baseline right-parenthesis EndFraction d x  (5.22)

A point force Fz located at x0 is represented by

bold-italic upper F prime Subscript z Baseline left-parenthesis x right-parenthesis equals bold-italic upper F Subscript z Baseline delta left-parenthesis x minus x 0 right-parenthesis  (5.23)

and thus

bold-italic w prime Subscript m Baseline equals StartFraction normal upper Phi Subscript w comma m Superscript asterisk Baseline left-parenthesis x 0 right-parenthesis bold-italic upper F Subscript z Baseline Over m prime left-parenthesis omega squared minus omega Subscript m Superscript 2 Baseline right-parenthesis EndFraction  (5.24)

From (3.110) we know that Fz=Myx, so we can deal with moment excitation using the same modal base

bold-italic w prime Subscript m Baseline equals minus integral Subscript 0 Superscript upper L Baseline StartStartFraction normal upper Phi Subscript w comma m Superscript asterisk Baseline StartFraction partial-differential bold-italic upper M prime Subscript y Over partial-differential x EndFraction left-parenthesis x right-parenthesis OverOver m prime left-parenthesis omega squared minus omega Subscript m Superscript 2 Baseline right-parenthesis EndEndFraction equals integral Subscript 0 Superscript upper L Baseline StartStartFraction StartFraction partial-differential normal upper Phi Subscript w comma m Superscript asterisk Baseline Over partial-differential x EndFraction bold-italic upper M prime Subscript y Baseline left-parenthesis x right-parenthesis OverOver m prime left-parenthesis omega squared minus omega Subscript m Superscript 2 Baseline right-parenthesis EndEndFraction  (5.25)

using the law of partial integration. With the moment My at x0 described as

bold-italic upper M prime Subscript y Baseline left-parenthesis x right-parenthesis equals bold-italic upper M Subscript y Baseline delta left-parenthesis x minus x 0 right-parenthesis  (5.26)

we get

bold-italic w prime Subscript m Baseline equals StartFraction normal upper Phi Subscript w comma m Superscript prime asterisk Baseline left-parenthesis x 0 right-parenthesis bold-italic upper F Subscript z Baseline Over m prime left-parenthesis omega squared minus omega Subscript m Superscript 2 Baseline right-parenthesis EndFraction with normal upper Phi Subscript w comma m Superscript prime asterisk Baseline left-parenthesis x right-parenthesis equals StartRoot StartFraction epsilon Subscript n Baseline Over upper L EndFraction EndRoot cosine left-parenthesis k Subscript n Baseline x right-parenthesis  (5.27)

As moments are linked to the rotations, the derivative of the mode shapes is used.

In Figure 5.2 the response of a beam excited at specific modal frequencies (top) and for a high frequency at different positions is shown.

Figure 5.2 Beam bending wave response calculated with the modal method.
Source: Alexander Peiffer.

The spectrum of the point impedance in Figure 5.3 approaches the value for infinite beams (3.136), but has many more peaks than the tube example for high frequencies. This results from the dispersion and the speed of sound that increases with frequency and therefore has fewer modes than rods or tubes.

Figure 5.3Scaled mechanical impedance of finite beam compared to infinite system.
Source: Alexander Peiffer.

5.3 Two-dimensional Systems

We deal with plates as an example for a realistic and representative two-dimensional system. In section 3.7 the equation of motion was given for in-plane displacement (longitudinal and transversal) and out-of-plane displacement (bending). The in-plane displacement is characterized by dispersion-free and high-speed wave propagation. Thus, the practical relevance of such systems is not very high as wavelengths stay large in the audible frequency range. For example, a steel plate has longitudinal wave speed of cLP=4600 m/s, meaning that we have a wavelength of λ=4.6 m at 1000 Hz. We would need very large systems to catch the first resonance of this wave type in the audible frequency range and in technical systems as for example a car. Thus, we stay with bending waves for the investigations on two-dimensional systems.

5.3.1 Bending Waves in Flat Plates

For the description of plate waves of finite systems we have to solve the homogenous form of (3.206)

normal upper Delta normal upper Delta bold-italic w minus omega Subscript n Superscript 2 Baseline StartFraction rho 0 h Over upper B EndFraction bold-italic w equals StartFraction bold-italic upper F double-prime Subscript z Baseline left-parenthesis x comma y right-parenthesis Over upper B EndFraction

with the following boundary conditions:

StartLayout 1st Row 1st Column w left-parenthesis x comma 0 right-parenthesis equals 0 2nd Column w left-parenthesis x comma upper L Subscript y Baseline right-parenthesis EndLayout equals 0  (5.28a)
StartLayout 1st Row 1st Column w left-parenthesis 0 comma y right-parenthesis equals 0 2nd Column w left-parenthesis upper L Subscript x Baseline comma y right-parenthesis EndLayout equals 0  (5.28b)
StartLayout 1st Row 1st Column upper M Subscript x Baseline left-parenthesis x comma 0 right-parenthesis equals minus upper B StartFraction partial-differential squared w Over partial-differential squared w EndFraction left-parenthesis 0 right-parenthesis equals 0 2nd Column upper M Subscript x Baseline left-parenthesis x comma upper L Subscript y Baseline right-parenthesis equals minus upper B StartFraction partial-differential squared w Over partial-differential y squared EndFraction left-parenthesis upper L Subscript y Baseline right-parenthesis equals 0 EndLayout  (5.28c)
StartLayout 1st Row 1st Column upper M Subscript x Baseline left-parenthesis 0 comma y right-parenthesis equals minus upper B StartFraction partial-differential squared w Over partial-differential x squared EndFraction left-parenthesis 0 right-parenthesis equals 0 2nd Column upper M Subscript y Baseline left-parenthesis upper L Subscript y Baseline comma y right-parenthesis equals minus upper B StartFraction partial-differential squared w Over partial-differential x squared EndFraction left-parenthesis upper L Subscript y Baseline right-parenthesis equals 0 EndLayout  (5.28d)

Figure 5.4Rectangular plate with edge translations fixed.
Source: Alexander Peiffer.

One can show using the same procedures as Sec. 5.2.2.1 that the function

normal upper Psi Subscript n Baseline left-parenthesis x comma y right-parenthesis equals sine left-parenthesis StartFraction n Subscript x Baseline pi x Over upper L Subscript x Baseline EndFraction right-parenthesis sine left-parenthesis StartFraction n Subscript y Baseline pi y Over upper L Subscript y Baseline EndFraction right-parenthesis  (5.29)

is a solution of Equation (3.206) with the modal frequencies

omega Subscript n Baseline equals StartRoot StartFraction upper B Over rho 0 h EndFraction EndRoot left-bracket left-parenthesis StartFraction n Subscript x Baseline pi Over upper L Subscript x Baseline EndFraction right-parenthesis squared plus left-parenthesis StartFraction n Subscript x Baseline pi Over upper L Subscript x Baseline EndFraction right-parenthesis squared right-bracket  (5.30)

and

k Subscript n Baseline equals StartRoot left-parenthesis StartFraction n Subscript x Baseline pi Over upper L Subscript x Baseline EndFraction right-parenthesis squared plus left-parenthesis StartFraction n Subscript x Baseline pi Over upper L Subscript x Baseline EndFraction right-parenthesis squared EndRoot  (5.31)

where n is a double index n=(nx,ny). These mode shapes are orthogonal and should be normalized for the product below the surface integral

integral Subscript 0 Superscript upper L Subscript x Baseline Baseline integral Subscript 0 Superscript upper L Subscript y Baseline Baseline normal upper Psi Subscript m Superscript asterisk Baseline left-parenthesis x comma y right-parenthesis normal upper Psi Subscript n Baseline left-parenthesis x comma y right-parenthesis d y d y equals delta Subscript m n Baseline StartFraction upper L Subscript x Baseline upper L y Over 4 EndFraction  (5.32)

leading to the normalised shape functions

normal upper Phi Subscript n Baseline left-parenthesis x comma y right-parenthesis equals StartFraction 2 Over StartRoot upper L Subscript x Baseline upper L Subscript y Baseline EndRoot EndFraction sine left-parenthesis StartFraction n Subscript x Baseline pi x Over upper L Subscript x Baseline EndFraction right-parenthesis sine left-parenthesis StartFraction n Subscript y Baseline pi y Over upper L Subscript y Baseline EndFraction right-parenthesis  (5.33)

Some shapes are shown in Figure 5.6. The mode count is estimated by the area method but in the wavenumber domain due to dispersion as shown in Figure 5.5. Without tangential modes there are no additional correction areas required.

Figure 5.5Wavenumber grid for plate waves.
Source: Alexander Peiffer.

Figure 5.6Some mode shapes of a flat rectangular plate. Dimensions Lx=1.0 m, Ly=1.8 m and h=2 mm.
Source: Alexander Peiffer.

5.3.1.1 Modal Density

We estimate the number of modes that occur below the wavenumber k by comparing the areas of the quarter wavenumber circle πk2/4 to the area covered by one wavenumber rectangle π2/(LxLy)

upper N Subscript 2 upper D Baseline left-parenthesis k right-parenthesis almost-equals StartFraction k squared upper L Subscript x Baseline upper L Subscript y Baseline Over 4 pi EndFraction  (5.34)

The modal density of the dispersive bending waves depends on the group velocity {modal density ! plate}

n Subscript 2 upper D Baseline left-parenthesis omega right-parenthesis equals StartFraction d upper N Over d omega EndFraction equals StartFraction d upper N Over d k EndFraction StartFraction d k Over d omega EndFraction almost-equals StartFraction k upper L Subscript x Baseline upper L Subscript y Baseline Over 2 pi c Subscript gr Baseline EndFraction equals StartFraction k upper L Subscript x Baseline upper L Subscript y Baseline Over 4 pi c Subscript upper B Baseline EndFraction equals StartFraction upper L Subscript x Baseline upper L Subscript y Baseline Over 4 pi EndFraction StartRoot StartFraction rho 0 h Over upper B EndFraction EndRoot  (5.35)

The dispersion of bending waves leads to the surprising effect that the modal density is constant over frequency.

5.3.1.2 Modal Response

The response of an excited plate can be given by the double sum running over both modal indexes n=(nx,ny).

bold-italic w left-parenthesis x comma y right-parenthesis equals sigma-summation Underscript n equals 1 Overscript normal infinity Endscripts bold-italic w prime Subscript n Baseline normal upper Phi Subscript n Baseline left-parenthesis x comma y right-parenthesis  (5.36)

Entering this into (3.206) we get the modal expression

sigma-summation Underscript n equals 1 Overscript normal infinity Endscripts m double-prime left-parenthesis omega Subscript n Superscript 2 Baseline minus omega squared right-parenthesis bold-italic w prime Subscript n Baseline normal upper Phi Subscript w comma n Baseline equals bold-italic upper F double-prime Subscript z Baseline left-parenthesis x comma y right-parenthesis  (5.37)

and multiplication with mode shapes Φm* and surface integration over the plate gives

StartLayout 1st Row 1st Column bold-italic w prime Subscript m 2nd Column equals StartFraction 1 Over m double-prime left-parenthesis omega Subscript m Superscript 2 Baseline minus omega squared right-parenthesis EndFraction integral Subscript 0 Superscript upper L Subscript x Baseline Baseline integral Subscript 0 Superscript upper L Subscript y Baseline Baseline normal upper Phi Subscript m Superscript asterisk Baseline left-parenthesis x comma y right-parenthesis bold-italic upper F double-prime Subscript z Baseline left-parenthesis x comma y right-parenthesis d y d y 2nd Row 1st Column Blank 2nd Column equals StartFraction bold-italic f prime Subscript m Baseline Over m double-prime left-parenthesis omega Subscript m Superscript 2 Baseline minus omega squared right-parenthesis EndFraction EndLayout  (5.38)

With modal forces

StartLayout 1st Row 1st Column bold-italic f prime Subscript m 2nd Column equals integral Subscript 0 Superscript upper L Subscript x Baseline Baseline integral Subscript 0 Superscript upper L Subscript y Baseline Baseline normal upper Phi Subscript m Superscript asterisk Baseline left-parenthesis x comma y right-parenthesis bold-italic upper F double-prime Subscript z Baseline left-parenthesis x comma y right-parenthesis d y d y EndLayout  (5.39)

A point force at (x0,y0) is represented by a double delta function to create the required force per area function

bold-italic upper F double-prime Subscript z Baseline left-parenthesis x comma y right-parenthesis equals delta left-parenthesis x minus x 0 right-parenthesis delta left-parenthesis y minus y 0 right-parenthesis bold-italic upper F Subscript z  (5.40)

leading to

bold-italic w left-parenthesis x comma y right-parenthesis equals sigma-summation Underscript n equals 1 Overscript normal infinity Endscripts StartFraction normal upper Phi Subscript n Baseline left-parenthesis x comma y right-parenthesis normal upper Phi Subscript n Superscript asterisk Baseline left-parenthesis x 0 comma y 0 right-parenthesis bold-italic upper F Subscript z Baseline Over m double-prime left-parenthesis omega Subscript n Superscript 2 Baseline minus omega squared right-parenthesis EndFraction  (5.41)

The mechanical point impedance is

bold-italic upper Z left-parenthesis x 0 comma y 0 right-parenthesis equals StartFraction bold-italic upper F Subscript z Baseline Over j omega bold-italic w EndFraction equals StartFraction 1 Over j omega EndFraction left-parenthesis sigma-summation Underscript n equals 1 Overscript normal infinity Endscripts StartFraction normal upper Phi Subscript n Baseline left-parenthesis x 0 comma y 0 right-parenthesis normal upper Phi Subscript n Superscript asterisk Baseline left-parenthesis x 0 comma y 0 right-parenthesis Over m double-prime left-parenthesis omega Subscript n Superscript 2 Baseline minus omega squared right-parenthesis EndFraction right-parenthesis Superscript negative 1  (5.42)

In Figure 5.7 an example for a point impedance is shown. The boundary impact can also be be neglected here for high frequencies and the impedance value for infinite values is reached. In the case of plates the shape of the impedance curve contains fewer peaks than the beam example. The higher dimensionality of the system provides more “space” for modes. Thus, the dynamic complexity of the system is reached earlier.

Figure 5.7Point impedance of plate (Lx=1m,Ly=1.8m,η=0.02) excited at r0=(0.7m,0.36m).
Source: Alexander Peiffer.

5.4 Reciprocity

Similar to the argument in Chapter 4, the reciprocity relationship also holds for structural equations. Inspecting (5.41) it becomes obvious that the quantities force at position 1 (and into direction 1) and the velocity at position 2 (and into direction 2) can be exchanged. Thus, reciprocity in structural dynamics reads as

StartFraction bold-italic v left-parenthesis bold r 2 right-parenthesis Over bold-italic upper F left-parenthesis bold r 1 right-parenthesis EndFraction equals StartFraction bold-italic v left-parenthesis bold r 1 right-parenthesis Over bold-italic upper F left-parenthesis bold r 2 right-parenthesis EndFraction  (5.43)

The same relationship can be found for displacement and acceleration, even though these quantities are not conjugate. But, they are power related, and a jω argument in Equation (5.41) does not change the above arguments. When proving the global principle, it can also be shown that this is also true for coupled systems. Thus, a volume source at position 1 generating a velocity at position 2 is equal to the force excitation at position 2 and the pressure response at position 1. This is of high practical use when the pressure signal of multiple force excitations at the engine mounts of a car are needed. A volume source with accelerometers at all mount positions replaces the experiment with one microphone at the head position and force excitation at every mount position. In complex geometries it may be hard to precisely excite the forces at positions that are not accessible. Placing accelerometers there is usually much easier.

Figure 5.8 Plate reponse to point force at r0=(0.7m,0.36m and frequency ω=800 Hz.
Source: Alexander Peiffer.

5.5 Numerical Solutions

Due to the fact that we started with mechanical systems of point masses, dampers, and springs, the formulation of the physical interpretation of the mass and stiffness matrices of structural finite elements is clear. In section 5.1 of this chapter, the global dynamic equation in discrete form was formulated. However, even without a deeper understanding, some global properties of finite element models should be given in order to understand the properties and the limits of finite element formulation.

5.5.1 Normal Modes in Discrete Form

In the previous sections of this chapter we learned that modal condensation is a useful tool to calculate the response of mechanical system. The modal method is intensively used in numerical or finite element methods, too. For investigations in later chapters, we will use a discrete variant of the analytical mode shapes from Equation (5.33). The discrete degrees of freedom are {qi} defined as shown in Figure 5.9 using a regular mesh. The node with index i is located in the xyplane with nodal position ri={xi,yi}T and the degree of freedom is the displacement in z, hence qi=w(xi,yi)

Figure 5.9Mesh for discrete mode shapes.
Source: Alexander Peiffer.

Thus, the modal vectors are defined by the nodal position and Equation (5.33)

Start 1 By 1 Matrix 1st Row normal upper Phi Subscript n Baseline EndMatrix equals upper A Start 4 By 1 Matrix 1st Row normal upper Phi Subscript n Baseline left-parenthesis x 1 comma y 1 right-parenthesis 2nd Row normal upper Phi Subscript n Baseline left-parenthesis x Subscript i Baseline comma y Subscript i Baseline right-parenthesis 3rd Row vertical-ellipsis 4th Row normal upper Phi Subscript n Baseline left-parenthesis x Subscript upper N Baseline comma y Subscript upper N Baseline right-parenthesis EndMatrix with upper N equals upper N Subscript x Baseline upper N Subscript y Baseline  (5.44)

In order to ascertain mass normalization, the mass matrix is required. We assume that the mass of the discretized plate is given by the related lumped mass and thus derived from the specific mass m times the element surface element that belongs to the specific node. So, we get a diagonal matrix with mass entries mi=ΔSm for inner elements, me=ΔSm/2 for the edges, and mv=ΔSm/4 for the vertex nodes.

Start 1 By 1 Matrix 1st Row upper M EndMatrix equals Start 5 By 5 Matrix 1st Row 1st Column m Subscript v Baseline 2nd Column Blank 3rd Column midline-horizontal-ellipsis 4th Column Blank 5th Column midline-horizontal-ellipsis 2nd Row 1st Column Blank 2nd Column m Subscript e Baseline 3rd Column Blank 4th Column Blank 5th Column Blank 3rd Row 1st Column vertical-ellipsis 2nd Column Blank 3rd Column down-right-diagonal-ellipsis 4th Column Blank 5th Column Blank 4th Row 1st Column Blank 2nd Column Blank 3rd Column Blank 4th Column m Subscript i Baseline 5th Column Blank 5th Row 1st Column vertical-ellipsis 2nd Column Blank 3rd Column Blank 4th Column Blank 5th Column down-right-diagonal-ellipsis EndMatrix  (5.45)

With this assumption the factor A=LxLyM with M as total mass of the plate provides mass normalised modeshapes that can be used for modal frequency analysis or modal condensation

normal upper Phi Subscript n Baseline left-parenthesis x Subscript i Baseline comma y Subscript i Baseline right-parenthesis equals StartFraction 2 Over StartRoot upper M EndRoot EndFraction sine left-parenthesis StartFraction n Subscript x Baseline pi x Subscript i Baseline Over upper L Subscript x Baseline EndFraction right-parenthesis sine left-parenthesis StartFraction n Subscript y Baseline pi y Subscript i Baseline Over upper L Subscript y Baseline EndFraction right-parenthesis with n equals left-parenthesis n Subscript x Baseline comma n Subscript y Baseline right-parenthesis  (5.46)

Due to the fact that the analytical solution is only sampled and the mesh doesn’t have to be fine enough to allow a precise numerical solution, quite coarse meshes can be used, e.g. four elements per wavelength. For a finite element model of the same plate, at least six (linear) elements or nodes per wavelength would be necessary for precise results Bathe (1982).

Bibliography

  1. Klaus-Jürgen Bathe. Finite Element Procedures in Engineering Analysis. Prentice-Hall Civil Engineering and Engineering Mechanics Series. Prentice-Hall, Englewood Cliffs, N.J, 1982.
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