3.6

  1. 2. 

    1. (a) 3;

    2. (b) 3;

    3. (c) 2

  2. 3. 

    1. (a) u2,u4,u5 are the column vectors of U corresponding to the free variables. u2=2u1,u4=5u1u3,u5=3u1+2u3

    2. (b) Hint: The column vectors of A satisfy the same dependency relations that the column vectors of U satisfy.

  3. 4. 

    1. (a) consistent;

    2. (b) inconsistent;

    3. (e) consistent

  4. 5. 

    1. (a) infinitely many solutions;

    2. (c) unique solution

  5. 6. Hint: Use the consistency theorem to determine if the system is consistent. If A is an m×n matrix with linearly dependent columns, then what can you conclude about its nullity? For a consistent system what does the nullity of the coefficient matrix tell you about the number of solutions?

  6. 7. 

    1. (b) Hint: If A has rank 6, then the column vectors of A will span 6.

  7. 8.  

    1. (a) Hint: If N(A)={0}, then what will the rank of A be?

    2. (b) Hint: Hint. Use the consistency theorem. If a system is consistent and N(A)={0}, then what can you conclude about the number of solutions? Alternatively, Theorem 3.3.2 could be helpful in answering these questions.

  8. 10. 

    1. (b) Hint: Whenever you represent a vector as a linear combination of linearly independent vectors, that representationwill be unique.

  9. 12. 

    1. (a) Hint: If A and B are row equivalent, then how are their ranks related?

    2. (b) Hint: Look at some examples. Make up a singular matrix A whose entries are all nonzero and then reduce A to its echelon form U. Do U and A have the same column spaces?

  10. 14. Hint: The column vectors of A satisfy the same dependency relations that the column vectors of U satisfy.

  11. 15. 

    1. (b) (ii). Hint: Use the equation Ax0=b to solve for a4.

  12. 16. Hint: Show that the system must be consistent and that the echelon form of the coefficient matrix will involve free variables.

  13. 18. 

    1. (b) n1

  14. 19. Hint: y=Ax0 is equivalent to saying that x is not in the null space of A.

  15. 21. Hint: If you have bases for the column spaces of A and B, you can use them to form a spanning for the column space of A+B.

  16. 22. 

    1. (a) Hint: Show that if xN(A) then xN(BA) and show the converse, if xN(BA) then xN(A).

    2. (b) Hint: Use part (a) to show first that (AC)T and AT have the same rank.

  17. 24. Hint: What is the rank of AB?

  18. 25. 

    1. (b) Hint: Partition B into columns and perform the block multiplication

      AB=A(b1,b2,...,bn)=(Ab1,Ab2,...,Abn)
  19. 27. 

    1. (b) Hint: Use the Rank-Nullity theorem.

  20. 28. 

    1. (a) Hint: Show that each column vector of C is a linear combination of the column vectors of A.

    2. (b) Hint: CT=BTAT.

  21. 29. 

    1. (a) Hint: In general a matrix E will have linearly independent column vectors if and only if Ex=0 has only the trivial solution x=0. One way to show that C has linearly independent column vectors is to show that Cx0 for all x0 and hence that Cx=0 has only the trivial solution.

    2. (b) Hint: CT=BTAT.

  22. 30. 

    1. (a) Hint: If the column vectors of B are linearly dependent then Bx=0 for some nonzero vector xr.

  23. 31. 

    1. (a) Hint: To get started, if C is a right inverse of A, let b be any vector in m and let c=Cb.

    2. (b) Hint: If n vectors span m then how must m and n be related?

  24. 32. If xj is a solution to Ax=ej for j=1,,m and X=(x1,x2,,xm) then AX=Im.

  25. 34. Hint: Let B be an n×m matrix. If B has a left inverse, then BT has a right inverse. Apply the result of Exercise 31 to BT.

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