Keyword arguments are assigned by keyword using the name=value syntax:

# arguments.keyword.py
def func(a, b, c):
    print(a, b, c)
func(a=1, c=2, b=3)  # prints: 1 3 2

Keyword arguments are matched by name, even when they don't respect the definition's original position (we'll see that there is a limitation to this behavior later, when we mix and match different types of arguments).

The counterpart of keyword arguments, on the definition side, is default values. The syntax is the same, name=value, and allows us to not have to provide an argument if we are happy with the given default:

# arguments.default.py
def func(a, b=4, c=88):
    print(a, b, c)

func(1)  # prints: 1 4 88
func(b=5, a=7, c=9)  # prints: 7 5 9
func(42, c=9)  # prints: 42 4 9
func(42, 43, 44)  # prints: 42, 43, 44

The are two things to notice, which are very important. First of all, you cannot specify a default argument on the left of a positional one. Second, note how in the examples, when an argument is passed without using the argument_name=value syntax, it must be the first one in the list, and it is always assigned to a. Notice also that passing values in a positional fashion still works, and follows the function signature order (last line of the example).

Try and scramble those arguments and see what happens. Python error messages are very good at telling you what's wrong. So, for example, if you tried something such as this:

# arguments.default.error.py
def func(a, b=4, c=88):
    print(a, b, c)
func(b=1, c=2, 42)  # positional argument after keyword one

You would get the following error:

$ python arguments.default.error.py
  File "arguments.default.error.py", line 4
    func(b=1, c=2, 42) # positional argument after keyword one
                  ^
SyntaxError: positional argument follows keyword argument

This informs you that you've called the function incorrectly.