Beyond the Basics

109. $f (x) = \frac{4 x + 2}{x};$ $f (x) = \frac{4 x + 2}{x};$ domain: $(- \infty, 0) \cup (0, \infty); f (4) = \frac{9}{2}$ $(- \infty, 0) \cup (0, \infty); f (4) = \frac{9}{2}$
111. $f (x) = \frac{2 - x}{x^{2} + 1};$ $f (x) = \frac{2 - x}{x^{2} + 1};$ domain: $(- \infty, \infty); f (4) = - \frac{2}{17}$ $(- \infty, \infty); f (4) = - \frac{2}{17}$
113. No, because they have different domains
115. No, because g is not defined at $- 1$ $- 1$
117. Yes
119. 3
121. $a = - 9, b = 6$ $a = - 9, b = 6$

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