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A switched dummy load

Introduction

A dummy load is a pure resistor of value 50 ohms which can replace your transmitting aerial and enable you to operate the transmitter for test purposes without radiating a signal. It sounds simple enough, but there are two main problems. Firstly, it is impossible to delve into your junk box and emerge with a resistor that will dissipate 100 W PEP and still retain its marked resistance value. Secondly, a ‘pure resistance’ is very difficult to achieve. A pure resistance is a device which has resistance but no reactance. All common resistors have significant reactance at radio frequencies, particularly the wire-wound varieties, which have a helical (i.e. wound like a coil) construction. This is particularly annoying, because wire-wound construction is normally used for large-wattage resistors.

Although all resistors have some reactance, not all are quite as bad as the wire-wound type. Carbon film resistors are made by depositing a thin film of carbon on the surface of a small, hollow ceramic cylinder, the thickness of the film of carbon determining the value of the resistor. Provided the lead lengths are kept short, these resistors have a tolerably small reactance, and will be used in this project.

Bearing the load

A 2 W carbon film resistor is hardly going to withstand our 100 W PEP of SSB, so it is obvious that the design of our dummy load must be a little more complex than a single resistor and a switch, despite what Figure 1 might suggest! In fact, it uses 20 resistors, each of value 1000 Ω (1 kΩ). How does this solve our problem?

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Figure 1 Basic circuit diagram

Perhaps a little theory is in order here, but no more than is required by the Radio Amateurs’ Examination.

When two equal resistors of value r are combined in parallel (i.e. side by side), the total resistance, RT, is given by:

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Adding 1/r to 1/r gives 2/r, therefore:

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So, by connecting two equal resistors in parallel, we get a combined resistance which is half the individual resistances. If we combine three in parallel, we get a third of the resistance, and so on.

Here, we are connecting 20 resistors of 1 kΩ in parallel, so we will produce an overall resistance of one-twentieth of the individual resistance, i.e. 1000/20 = 50 Ω, which is what we set out to achieve!

This is not the only advantage, though. Each resistor is capable of dissipating 2 W, so 20 of them will safely dissipate 40 W, for short periods at least. This power dissipation is approximately the same as 100 W PEP of normal speech, so the design should be capable of use in an ‘average’ amateur station. The power-handling ability of any dummy load can be improved by providing a ‘heat sink’ which helps to conduct the heat energy away from the resistors, thus lowering their temperature. One popular heat sink is a can of transformer oil, into which the resistors are immersed. This design uses a rather more mundane heat sink, but which is adequate for the job in hand.

Pouring the heat away

Two basic PCBs are needed, the details being given in Figure 2. Both measure 11 × 35 mm. Each has a set of 20 holes of diameter about 1 mm to take the ends of the resistors. Only one of them has two 3 mm holes which are used for mounting the completed load. Figure 3 shows how the heat sink is assembled. Solder one end of each resistor into the ‘earth’ PCB, and then mount this to the box using the two bolts as shown in the diagram. Between each rank of resistors is a ‘sandwich’ consisting of an aluminium strip and two pieces of ceramic wall tile, to act as a heat sink for the resistors. Heat sink compound is used to provide good thermal contact between the resistors and the tiles, and between the tiles and the aluminium strip. This is shown in the lower part of Figure 3. Thread the loose wires of the resistors through the holes in the second PCB, solder into place, and crop the protruding wires.

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Figure 2 PCB resistor supports

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Figure 3 Switched dummy load, component layout

Switching

A changeover switch must be used so that the transceiver can be switched between the dummy load and the aerial without unscrewing connectors. For most purposes, an ordinary 10 A 230 V changeover switch will suffice, as found in many electrical shops and DIY stores.

Wire this into the circuit as shown in Figure 1 and Figure 3. Check your wiring. Put S1 in the ‘dummy load’ position. If you have a multimeter which includes an ohmmeter, measure the resistance across the socket, J1, before connecting it to the transceiver. It should be very near 50 Ω. With S1 in the ‘aerial’ position, there should be an infinite resistance across J1. Move your ohmmeter to read the resistance across J2. It should be infinite for both positions of S1. If all seems correct, close the box and your dummy load is ready for use!

Parts list

Resistors

1000 Ω (1 kΩ) 2 W carbon film, 20 required

Additional items

10 A 230 V changeover (SPDT) switch

SO–239 sockets, 2 required

Aluminium box 120 × 95 × 53 mm or similar

Ceramic wall tile cut as required

Aluminium strip, 18 SWG

Nuts and bolts as required

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