1. P=[1121], D=[1002], A5=[6331−62−30]
2. P=[1121], D=[−1002], A5=[6533−66−34]
3. P=[1132], D=[0002], A5=[9664−96−64]
4. P=[1132], D=[1002], A5=[9462−93−61]
5. P=[1143], D=[1002], A5=[12593−124−92]
6. P=[2151], D=[1002], A5=[15662−310−123]
7. P=⎡⎣⎢100001310⎤⎦⎥, D=⎡⎣⎢100020002⎤⎦⎥, A5=⎡⎣⎢100933200032⎤⎦⎥
8. P=⎡⎣⎢012100101⎤⎦⎥, D=⎡⎣⎢100010002⎤⎦⎥, A5=⎡⎣⎢100−621−6231032⎤⎦⎥
9. P=⎡⎣⎢100101−310⎤⎦⎥, D=⎡⎣⎢100020002⎤⎦⎥, A5=⎡⎣⎢100−9332031032⎤⎦⎥
10. P=⎡⎣⎢110−102320⎤⎦⎥, D=⎡⎣⎢100020002⎤⎦⎥, A5=⎡⎣⎢94620−93−610313132⎤⎦⎥
11. P=⎡⎣⎢0−130−25−1−4287⎤⎦⎥, D=⎡⎣⎢−100000001⎤⎦⎥, A10=⎡⎣⎢178−1950−5150−26⎤⎦⎥
12. P=⎡⎣⎢120105350⎤⎦⎥, D=⎡⎣⎢−100010001⎤⎦⎥, A10=⎡⎣⎢100010001⎤⎦⎥
13. P=⎡⎣⎢−102110111⎤⎦⎥, D=⎡⎣⎢−100000001⎤⎦⎥, A10=⎡⎣⎢320−3−20111⎤⎦⎥
14. P=⎡⎣⎢102110211⎤⎦⎥, D=⎡⎣⎢−100000001⎤⎦⎥, A10=⎡⎣⎢320−3−20111⎤⎦⎥
15. A2−3A+2I=0, A3=[2921−28−20], A4=[6145−60−44], A−1=12[−2−345]
16. A2−3A+2I=0, A3=[3614−70−27], A4=[7630−150−59], A−1=12[−3−2106]
17. −A3+5A2−8A+4I=0, A3=⎡⎣⎢1002180008⎤⎦⎥, A4=⎡⎣⎢100451600016⎤⎦⎥, A−1=12⎡⎣⎢200−310001⎤⎦⎥
18. −A3+4A2−5A+2I=0, A3=⎡⎣⎢100−141−14708⎤⎦⎥, A4=⎡⎣⎢100−301−3015016⎤⎦⎥, A−1=12⎡⎣⎢200222−101⎤⎦⎥
19. −A3+5A2−8A+4I=0, A3=⎡⎣⎢100−2180708⎤⎦⎥, A4=⎡⎣⎢100−4516015016⎤⎦⎥, A−1=12⎡⎣⎢200310−101⎤⎦⎥
20. −A3+5A2−8A+4I=0, A3=⎡⎣⎢22140−21−130778⎤⎦⎥, A4=⎡⎣⎢46300−45−290151516⎤⎦⎥, A−1=12⎡⎣⎢−1−20340−1−11⎤⎦⎥
21. −A3+A=0, A3=A=A=⎡⎣⎢162105−1502−6⎤⎦⎥, A4=A2=⎡⎣⎢178−1950−5150−26⎤⎦⎥. Because λ=0 is an eigenvalue, A is singular and A−1 does not exist.
22. −A3+A2+A−I=0, A3=A=⎡⎣⎢11200−6−110−2−41⎤⎦⎥=A, A4=⎡⎣⎢100010001⎤⎦⎥=I, A−1=A
23. −A3+A=0, A3=A=⎡⎣⎢124−1−2−4111⎤⎦⎥, A4=A2=⎡⎣⎢320−3−20111⎤⎦⎥. Because λ=0 is an eigenvalue, A is singular and A−1 does not exist.
24. −A3+A=0, A3=A= ⎡⎣⎢524−5−2−4−3−1−3⎤⎦⎥, A4=A2=⎡⎣⎢320−3−20−1−11⎤⎦⎥. Because λ=0 is an eigenvalue, A is singular and A−1 does not exist.
25. xk=Akx0=[11−11][1004/5]k12[1−111]x0→=(C0+S0)[1/21/2] as k→∞. The long-term distribution of population is 50% city, 50% suburban.
26. xk=Akx0=[13−11][1004/5]k14[1−311]x0→=(C0+S0)[1/43/4] as k→∞. The long-term distribution of population is 25% city, 75% suburban.
27. xk=Akx0=[35−11][1003/5]k18[1−513]x0→=(C0+S0)[3/85/8] as k→∞. The long-term distribution of population is 3/8 city, 5/8 suburban.
28. xk=Akx0=[12−11][1007/10]k13[1−211]x0→=(C0+S0)[1/32/3] as k→∞. The long-term distribution of population is 1/3 city, 2/3 suburban.
29. xk=Akx0=[12−11][10017/20]k13[1−211]x0→=(C0+S0)[1/32/3] as k→∞. The long-term distribution of population is 1/3 city, 2/3 suburban.
30. xk=Akx0=[34−11][10013/20]k17[1−413]x0→=(C0+S0)[3/74/7] as k→∞. The long-term distribution of population is 3/7 city, 4/7 suburban.
31. xk=Akx0=[5452][1004/5]k110[−245−5]x0→=[2.5R0−F02R0−0.8F0] as k→∞. The fox-rabbit population approaches a stable situation with 2.5R0−F0 foxes and 2R0−0.8F0 rabbits.
32. xk=Akx0=[10721][19/200017/20]k14[−172−10]x0→=[00] as k→∞. The fox and rabbit population both die out.
33. xk=Akx0=[109103][21/20003/4]k160[−3910−10]x0≈160(1.05)k(10R0−3F0)[109] as when k is sufficiently large. The fox and rabbit populations are both increasing at 5% per year, with 10 foxes for each 9 rabbits.
34. A=PDP−1=[4156−30−41]. If n is even, then Dn=I so An=PDnP−1=PIP−1=I. If n is odd, then An=An−1A=IA=A. Thus A99=A and A100=I.
35. λ=±1 implies that Dn=I if n is even, in which case An=PDnP−1=I.
36. A2=I, so A3=A2A=IA=A, A4=A3A=A2=I, and so forth.
37. A2=−I, so A3=A2A=−IA=−A, A4=A3A=−A2=I, and so forth.
38. If B=[0010] so B2=0, and it follows that An=I+nB=[10n1].