1. y(x)=x2+x+3
2. y(x)=13(x−2)3+1
3. y(x)=13(2x3/2−16)
4. y(x)=−1/x+6
5. y(x)=2x+2−−−−−√−5
6. y(x)=13[(x2+9)3/2−125]
7. y(x)=10 tan−1 x
8. y(x)=12 sin 2x+1
9. y(x)=sin−1 x
10. y(x)=−(x+1)e−x+2
11. x(t)=25t2+10t+20
12. x(t)=−10t2−15t+5
13. x(t)=12t3+5t
14. x(t)=13t3+12t2−7t+4
15. x(t)=13(t+3)4−37t−26
16. x(t)=43(t+4)3/2−5t−293
17. x(t)=12[(t+1)−1+t−1]
19. x(t)={5t10t−12t2−252if 0≤t≤5,if 5≤t≤10.
20. x(t)={12t25t−252if 0≤t≤5,if 5≤t≤10.
21. x(t)={12t210t−12t2−25if 0≤t≤5,if 5≤t≤10.
22. x(t)=⎧⎩⎨⎪⎪⎪⎪⎪⎪56t25t−15216(−5t2+100t−290)if 0≤t≤3,if 3≤t≤7,if 7≤t≤10.
23. v(t)=−(9.8)t+49, so the ball reaches its maximum height (v=0) after t=5 seconds. Its maximum height then is y(5)=122.5(m).
24. v(5)=−160 ft/s
25. The car stops when t≈2.78 (s), so the distance traveled before stopping is approximately x(2.78)≈38.58 (m).
26. (a) y≈530 m (b) t≈20.41 s (c) t≈20.61 s
27. y0≈178.57 (m)
28. v(4.77)≈−192.64 ft/s
29. After 10 seconds the car has traveled 200 ft and is traveling at 70 ft/s.
30. a=22 ft/s2; it skids for 4 seconds.
31. v0=1030−−√ (m/s), about 197.18 km/h
32. 60 m
33. 2010−−√≈63.25 (ft/s)
34. 460.8 ft
36. About 13.6 ft
37. 25 (mi)
38. 1:10 pm
39. 6 mph
40. 2.4 mi
41. 5443≈181.33 (ft/s)
42. 25 mi
43. Time: 6.12245×109 s≈194 years;
Distance: 1.8367×1017 m≈19.4 light-years
44. About 54 mi/h