The following is the disassembled output of a program; let's translate the following code to its high-level equivalent. Use the techniques and the concepts that you learned previously to solve this challenge:

mov dword ptr [ebp-4], 1
cmp dword ptr [ebp-4], 0
jnz loc_40101C
mov eax, [ebp-4]
xor eax, 2
mov [ebp-4], eax
jmp loc_401025

loc_40101C:
 mov ecx, [ebp-4]
 xor ecx, 3
 mov [ebp-4], ecx

loc_401025: