Let's translate the following code into its high-level equivalent. Use the techniques and the concepts that you have learned so far to solve this challenge:

 mov dword ptr [ebp-8], 0
 mov dword ptr [ebp-4], 0

loc_401014:
 cmp dword ptr [ebp-4], 4
 cmp dword ptr [ebp-4], 4
 jge loc_40102E
 mov eax, [ebp-8]
 add eax, [ebp-4]
 mov [ebp-8], eax
 mov ecx, [ebp-4]
 add ecx, 1
 mov [ebp-4], ecx
 jmp loc_401014

loc_40102E: