2.27.  TOTAL SOLUTION OF THE STATE EQUATION

The purpose of this section is to illustrate how one may obtain the complete solution for the output in the time domain of a control system utilizing the state-variable method. In this example, we will want to determine the complete solution by evaluating Eq. (2.255), the state transition equation.

Consider a system described by the following differential equation:

Image

It is desired to determine the output c(t), given that the input r(t) is given by

Image

and the initial conditions are c(0) = 1 and Image(0) = 0. The technique employed is to determine the state transition matrix from Eq. (2.256) and then evaluate Eq. (2.255) for x(t). The output c(t) is then evaluated from

Image

If the state variables are defined by

Image

and u(t) by

u(t) = r(t),

then the system can be described by the following two first-order differential equations:

Image

Therefore, the system can be described by

Image

where

Image

The state transition matrix, which is defined by Eq. (2.256), can be obtained from Eq. (2.301). We find

Image

From Eq. (2.188), we know that

Image

Therefore,

Image

The state transition matrix defined by Eq. (2.256) is the inverse transform of this matrix. It is given by

Image

The full solution for the output can be obtained from Eqs. (2.255) and (2.297) as follows:

Image

Image

Substituting Eq. (2.306) into Eq. (2.307), we obtain the following relationship for the output in terms of the state transition matrix:

Image

We know Φ(t) from Eq. (2.305). We have looked at many similar systems in this chapter, and should know by inspection now that

Image

For this system, the input function u(τ) + Image(τ) is obtained as follows:

Image

Substituting all of these values into Eq. (2.308), we obtain the following expression:

Image

On simplifying, the result becomes

Image

Integrating and simplifying, we finally obtain the output as

Image

We can check the reasonableness of this result by determining the initial value, c(0). Substituting t = 0 into Eq. (2.313), we obtain

Image

which agrees with the value of c(0) specified. It is left as an exercise to the reader to also check that c(0) = 0 which was also specified.

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