Exercises 22.5, page 641

1. $UCL (\bar{x}) = 504.7 mg, LCL (\bar{x}) = 494.7 mg$ $UCL (\bar{x}) = 504.7 mg, LCL (\bar{x}) = 494.7 mg$
3. The first point would be below the $\bar{x}$ $\bar{x}$ line at 499.7. The UCL and LCL lines would be 0.2 unit lower.
5. $\bar{\bar{x}} = 361.8 N ∙ m, UCL = 368.9 N ∙ m, LCL = 354.6 N ∙ m$ $\bar{\bar{x}} = 361.8 N ∙ m, UCL = 368.9 N ∙ m, LCL = 354.6 N ∙ m$
7.
9. $\bar{\bar{x}} = 8.986 V, UCL = 9.081 V, LCL = 8.890 V$ $\bar{\bar{x}} = 8.986 V, UCL = 9.081 V, LCL = 8.890 V$
11.
13. $μ = 2.725 in ., UCL = 2.768 in ., LCL = 2.682 in .$ $μ = 2.725 in ., UCL = 2.768 in ., LCL = 2.682 in .$
15. $μ_{R} = 5.57 mL, UCL = 11.17 mL, LCL = 0.00 mL$ $μ_{R} = 5.57 mL, UCL = 11.17 mL, LCL = 0.00 mL$
17. $\bar{p} = 0.0369, UCL = 0.0548, LCL = 0.0190$ $\bar{p} = 0.0369, UCL = 0.0548, LCL = 0.0190$
19. $\bar{p} = 0.0580, UCL = 0.0894, LCL = 0.0266$ $\bar{p} = 0.0580, UCL = 0.0894, LCL = 0.0266$

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Table of Contents for Exercises 22.5, page 641