Chapter 1

  1. 1. 9 + 16 = 25 = 5

  2. 2. (7)( − 3)( − 2)( − 6)(0) is undefined (division by zero).

  3. 3. 3.372 × 10 − 37.526 × 1012 = 4.480 × 10 − 16

    A calculator screen with input 3.372 E negative 3 divided by 7.526 E 12, and output 4.48046771 E negative 16.

  4. 4. ( + 6)( − 2) − 3( − 1)5 − 2 =  − 12 − ( − 3)3 =  − 12 + 33 =  − 93 =  − 3

  5. 5. 346.4 − 23.5287.7 − 0.9443(3.46)(0.109) =  − 1.108

    A calculator screen with input 346.4 minus 23.5, divided by 287.7 minus 0.944 cubed divided by, 3.46 times 0.109, and output negative 1.10820764.

  6. 6. (2a0b − 2c3) − 3 = 2 − 3a0( − 3)b( − 2)( − 3)c3( − 3) = 2 − 3a0b6c − 9 = b68c9

  7. 7. (2x + 3)2 = (2x + 3)(2x + 3) = 2x(2x) + 2x(3) + 3(2x) + 3(3) = 4x2 + 6x + 6x + 9 = 4x2 + 12x + 9

  8. 8. 3m2(am − 2m3) = 3m2(am) + 3m2( − 2m3) = 3am3 − 6m5

  9. 9. 8a3x2 − 4a2x4 − 2ax2 = 8a3x2 − 2ax2 − 4a2x4 − 2ax2 =  − 4a2 − ( − 2ax2) =  − 4a2 + 2ax2

  10. 10. 3x − 52x − 16x2 − 13x + 76x2 − 3x_  − 10x + 7 − 10x + 5_ 2(quotient)(remainder)

  11. 11. (2x − 3)(x + 7) = 2x(x) + 2x(7) + ( − 3)(x) + ( − 3)(7) = 2x2 + 14x − 3x − 21 = 2x2 + 11x − 21

  12. 12. 3x − [ 4x − (3 − 2x)]  = 3x − [ 4x − 3 + 2x]  = 3x − [ 6x − 3]  = 3x − 6x + 3 =  − 3x + 3

  13. 13. 5y − 2(y − 4) = 75y − 2y + 8 = 73y + 8 − 8 = 7 − 83y =  − 1y =  − 1/3

  14. 14. 3(x − 3) = x − (2 − 3d)3x − 9 = x − 2 + 3d3x − 9 − x + 9 = x − 2 + 3d − x + 92x = 3d + 7x = 3d + 72

  15. 15. 245 lb / ft3 = 245 lb1 ft3 × 1 kg2.205 lb × 1 ft328.32 L = 245(1)(1) kg1(2.205)(28.32) L = 3.92 kg / L

  16. 16. 0.0000036 = 3.6 × 10 − 6 (six places to right)

  17. 17.  

     − π  − 3 0.3 2 |  − 4|  (order)
     − 3.14  − 3 0.3 1.41 4 (value)
  18. 18. 3(5 + 8) = 3(5) + 3(8) illustrates the distributive law.

  19. 19.

    1. 5,

    2. 3.0 (zero is significant)

  20. 20. Evaluation: 1000(1 + 0.05/2)2(3) = 1000(1.025)6 = $1159.69

  21. 21. 8(100 − x)2 + x2 = 8(100 − x)(100 − x) + x2 = 8(10 , 000 − 200x + x2) + x2 = 80 , 000 − 1600x + 8x2 + x2 = 80 , 000 − 1600x + 9x2

  22. 22. L = L0[ 1 + α(t2 − t1)] L = L0[ 1 + αt2 − αt1] L = L0 + αL0t2 − αL0t1L − L0 + αL0t1 = αL0t2t2 = L − L0 + αL0t1αL0

  23. 23. Let n = number of pounds of second alloy

    0.3(20) + 0.8n = 0.6(n + 20)6 + 0.8n = 0.6n + 120.2n = 6n = 30 lb

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